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sammy [17]
3 years ago
11

Solve the following system of equations for all three variables.

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
7 0

Answer:

Step-by-step explanation:

-2x + 3y – 4z = 8    ----------------(I)

5x – 3y + 5z = -8    -----------------(II)

7x – 3y + 3z = 8 ------------------(III)

Add equation (I) & (II) and thus y will be eliminated

(I)        -2x + 3y – 4z = 8

(II)        <u>5x – 3y + 5z = -8</u>    {Add}

           3x          + z  = 0   ------------------------(A)

Multiply equation (II) by (-1) and then add with equation (III). Thus y will be eliminated.

(II) * (-1)         -5x + 3y - 5z = +8

                     <u>7x – 3y + 3z = 8</u>   {Add}

                     2x         -2z   = 16   ---------------(B)

Multiply equation (A) by 2 and then add. Thus z will be eliminated and we will get the value of x

(A) * 2          6x + 2z = 0

(B)                 <u>2x - 2z  = 16</u>   {Add}

                     8x         = 16

Divide both sides by 8

                             x = 16/8

                          x = 2

Plugin x = 2 in equation (A)

3x + z = 0

3*2 + z = 0

 6 + z = 0

       z = -6

Plug in x = 2 and z  = - 6 in equation (I)

-2x +3y - 4z = 8

-2*2 + 3y - 4*(-6) = 8

-4 + 3y + 24 = 8

     3y   + 20 = 8

               3y = 8 - 20

               3y = -12

                 y = -12/3

y = -4

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lbvjy [14]3 years ago
5 0

Answer: Given equations

2x+3y−z=6  →(1)

x−y+7z=8    →(2)

3x−y+2z=7     →(3)

(1)+3×(2)  

2x+3y−z+3x−3y+21z=6+24

5x+20z=30

x+4z=6    →(4)

(3)−(2)

2x−5z=−1   →(5)

2×(4)−(5)

2x+8z−2x+5z=12=1

13z=13

z=1

x=6−4z  

x=2

⇒  2(2)+3y−1=6

y=1

∴   x=2,y=1,z=1 is solution of given equations.

Step-by-step explanation: hope it is help full

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3 years ago
Please assist me with #5, 6, 7, 8​
Leona [35]

Answer:

5a. -0.4 m/s²

5b. 290 m

6. 12.9 s

7. 100 s

8. 17.2 km/hr

Step-by-step explanation:

5. "While approaching a police officer parked in the median, you accelerate uniformly from 31 m/s to 27 m/s in a time of 10 s.

a. What is your acceleration?

b. How far do you travel in that time?"

Given:

v₀ = 31 m/s

v = 27 m/s

t = 10 s

Find: a and Δx

v = at + v₀

(27 m/s) = a (10 s) + (31 m/s)

a = -0.4 m/s²

Δx = ½ (v + v₀) t

Δx = ½ (27 m/s + 31 m/s) (10 s)

Δx = 290 m

6. "If a pronghorn antelope accelerates from rest in a straight line with a constant acceleration of 1.7 m/s², how long does it take for the antelope to reach a speed of 22 m/s?"

Given:

v₀ = 0 m/s

v = 22 m/s

a = 1.7 m/s²

Find: t

v = at + v₀

(22 m/s) = (1.7 m/s²) t + (0 m/s)

t = 12.9 s

7. "A 1200 kg airplane starts from rest and moves forward with a constant acceleration of 5 m/s² along a runway that is 250 m long. How long does it take the plane to travel the 250 m?"

Given:

v₀ = 0 m/s

a = 5 m/s²

Δx = 250 m

Find: t

Δx = v₀ t + ½ at²

(250 m) = (0 m/s) t + ½ (5 m/s²) t²

t = 100 s

8. "During a marathon, a runner runs the first 10 km in 0.58 hours, the next 10 km in 0.54 hours and the last 10 km in 0.62 hours.  What is the average speed of the runner during that marathon?"

This isn't a constant acceleration problem, so there's no need for a chart.

Average speed = total distance / total time

v = (10 km + 10 km + 10 km) / (0.58 hr + 0.54 hr + 0.62 hr)

v = 30 km / 1.74 hr

v = 17.2 km/hr

3 0
3 years ago
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