243log(81x)=48
log(81x)=48÷243
log(81x)=16÷81
81x=10^(16÷81)
81x= 81sqaure root pf 10^16
divide by 81
x =.0194557
9514 1404 393
Answer:
x = 4
Step-by-step explanation:
Corresponding segments of similar triangles are proportional. Here, the similar triangles are ...
ΔABC ~ ΔADE
so the relationship between the sides is ...
BC/BA = DE/DA . . . . . . we put the unknown value in the numerator
x/4 = 12/(4+8)
x = 4(1) = 4
The length of side x is 4.
Answer: The expression is 7/2.
<h3>
Answer: -20</h3>
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Work Shown:
Let x be the location of E on the number line.
Since C is the midpoint of E and F, this means we can find C's location by adding E and F together and dividing that sum by 2
midpoint = (endpoint1 + endpoint2)/2
C = (E+F)/2
Plug in E = x, C = -8 and F = 4. Then solve for x
C = (E+F)/2
-8 = (x+4)/2
(x+4)/2 = -8
x+4 = 2(-8) .... multiplying both sides by 2
x+4 = -16
x = -16-4 .... subtract 4 from both sides
x = -20
The location of point E on the number line is -20
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As a check, lets add E and F to get E+F = -20+4 = -16
Then cut this in half to get -16/2 = -8, which is the proper location of point C
This confirms our answer.
Gideon is painting all sides thus we find the overall area of the square pyramid given in the picture. A square pyramid is a polyhedron that consists of a square and 4 triangles. To solve the area that Gideon will have to paint, we can calculate the area of the square and the area of the triangles then add these two values of area. We proceed as follows:
Area of the square = s^2 where s is the measure of the side
Area of the square = 4^2 = 16 in^2
Area of the triangle= 1/2 bh where b is the base of the triangle and h is height of the triangle
Area of the triangle = 1/2 (4) (5) = 10 in^2
We multiply the area of the triangle to four in order to obtain the total area of the triangles.
Total area of the triangles = 4 x 10 = 40 in^2
We then add the two areas,
Total Area = 16 + 40 = 56 in^2
Thus the total area that Gideon will have to paint for one square pyramid is 56 in^2.
