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Artemon [7]
3 years ago
14

What is the value of 4^6/4^8A. 1/1024B. 1/256C. 1/64D. 1/16​

Mathematics
2 answers:
Gnom [1K]3 years ago
8 0

Answer:

1/16

Step-by-step explanation:

We know that a^b / a^c = a^(b-c)

4^6/4^8

4^(6-8)

4^-2

We know that a^-b = 1/a^b

1/4^2

1/16

azamat3 years ago
5 0

Answer:

D

Step-by-step explanation:

Using the rule of exponents

\frac{a^{m} }{a^{n} } with n > m

= \frac{1}{a^{(n-m)} } , then

\frac{4^{6} }{4^{8} }

= \frac{1}{4^{(8-6)} }

= \frac{1}{4^{2} }

= \frac{1}{16} → D

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Write a relationship for a function whose k(x) values are 5 more than four times the principal square root of x .
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Answer:

k(x)=5+4\sqrt{x}

Step-by-step explanation:

Write a function whose k(x) values are 5 more than four times the principal square root of x.

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k(x)=5+4\sqrt{x}

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Step-by-step explanation:

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3 years ago
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Need help ASAP !!!!!!
Slav-nsk [51]

Answer:

Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.  

Step-by-step explanation:

Given:

Let,

point S( x₁ , y₁) ≡ ( -1 , 1)  

point T( x₂ , y₂) ≡ (3 , -5)

Point M( x , y ) is the Mid point of segment ST.  

To Find:

Point M( x , y )= ?

Solution:

As Point M( x , y ) is the Mid point of segment ST.

So we have Mid Point Formula as

Mid\ pointM(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})

On substituting the given values in above equation we get

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Therefore, Point M( 1 , -2 ) is the Mid point of segment ST.  

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