Answer:
x=√40
Step-by-step explanation:
In above figure,
h=7
b=3
p=x=?
Now,
by Pythagoras theorem,

<span>30 is the answer the answer is 30</span>
Answer:
Step-by-step explanation:
From the given information:
ΔG° = -30.5 kJ/mol
By applying the following equation to calculate the value of K.
ΔG° =-RT㏑K
making ㏑ K the subject of the formula:

where;
Temperature at 25° C = (25 + 273)K
= 298K
R = 8.3145 J/mol.K (gas cosntant)


㏑K = 12.309

K = 221682.17
K = 2.22 × 10⁵
b) The reaction for the metabolism of glucose is given as:

From the above expression, let calculate the Gibbs free energy by using the formula:

![\Delta G^0_{rx n }= [6 \times \Delta G^0_{f}(CO_2) + 6 \times \Delta G^0_{f}(H_2O)] - [1 \times \Delta G^0_{f}(C_6H_{12}O_6) + 6 \times \Delta G^0_{f}(O_2)]](https://tex.z-dn.net/?f=%5CDelta%20G%5E0_%7Brx%20n%20%7D%3D%20%5B6%20%5Ctimes%20%5CDelta%20G%5E0_%7Bf%7D%28CO_2%29%20%2B%206%20%5Ctimes%20%5CDelta%20G%5E0_%7Bf%7D%28H_2O%29%5D%20-%20%5B1%20%5Ctimes%20%5CDelta%20G%5E0_%7Bf%7D%28C_6H_%7B12%7DO_6%29%20%2B%206%20%5Ctimes%20%5CDelta%20G%5E0_%7Bf%7D%28O_2%29%5D)
At standard conditions;
The values of corresponding compounds are substituted into the equation above:
Thus,
![\Delta G^0_{rx n }= [6 \times (-394) + 6 \times (-237)] - [1 \times (-911) + 6 \times (0)] \ kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20G%5E0_%7Brx%20n%20%7D%3D%20%5B6%20%5Ctimes%20%28-394%29%20%2B%206%20%5Ctimes%20%28-237%29%5D%20-%20%5B1%20%5Ctimes%20%28-911%29%20%2B%206%20%5Ctimes%20%280%29%5D%20%5C%20kJ%2Fmol)
![\Delta G^0_{rx n }= [-2364-1422] - [-911+0] \ kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20G%5E0_%7Brx%20n%20%7D%3D%20%5B-2364-1422%5D%20-%20%5B-911%2B0%5D%20%5C%20kJ%2Fmol)



Now, the no of ATP molecules generated = 
= (-2875000 J/mol ) / -30500 J/mol
= 94.26
≅ 94 ATP molecules generated
Answer:
SSS
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Even function has following property:</u>
<u>It is easy to show this works with the second choice only. All the others don't work:</u>
- g(x) = (x - 1)² + 1
- g(-x) = (-x - 1)² + 1
This is not correct as x - 1 ≠ -x - 1 so as their squares, so g(x) ≠ g(-x)
The last two choices are not even similarly.