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Wittaler [7]
3 years ago
11

A car travelled at a constant speedof 40m/s for 4.5 s. Calculate the distance covered

Mathematics
1 answer:
gregori [183]3 years ago
6 0

Answer:

180m

Step-by-step explanation:

you multiply 40 by 4.5 and get 180m

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2/3 times 3/4<br> What is the answer?
umka21 [38]

Answer:

6/12 simplified: 1/2

Step-by-step explanation:

You just multiply the numerator by the numerator and the denominator by the denominator... 2x3 and 3x4

Hope you understand... if you have any questions just message in the box : D

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A 5-pound of flour costs $4.80. For this bag of flour, what is the cost of flour per ounce?
sattari [20]
So we convert money into numbers 5 pounds of flour is 480 OK. Then we multiply 5*16 we get 80 then 480/80=006. Then we convert money back to numbers and we get 0.006. Answer A is correct.
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3 years ago
What is 80% of 72 ? pls help due today
Leni [432]

Answer:

Step-by-step explanation:

57.6

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3 years ago
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The graph of F ( x ) = 4/x2 - 2x - 3 is shown <br> for which values of X is f ( x ) decreasing
Elza [17]

Hi there!

\large\boxed{(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty) }

We can find the values of x for which f(x) is decreasing by finding the derivative of f(x):

f(x) = \frac{4}{x^2} - 2x - 3

Taking the derivative gets:

f'(x) = -\frac{8}{x^3} - 2

Find the values for which f'(x) < 0 (less than 0, so f(x) decreasing):

0 = -8/x³ - 2

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2x³ = -8

x³ = -4

x = \sqrt[3]{-4}

Another critical point is also where the graph has an asymptote (undefined), so at x = 0.

Plug in points into the equation for f'(x) on both sides of each x value to find the intervals for which the graph is less than 0:

f'(1) = -8/1 - 2 = -10 < 0

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f'(-2) = -8/-8 - 2 = -1 < 0

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(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty)

6 0
3 years ago
100 points!!!! To whoever helps me with this!
netineya [11]

Answer:

#1: Josue's dogs

#2: see images

#3: Am group median: 25.5       Pm group median: 19

#4: Am group first Quartile = 16 Pm group first Quartile = 10

#5: Am group third Quartile = 30 Pm group third Quartile = 37

#6: see images

#7: Am group Interquartile Range = 14 Pm group Interquartile Range = 27

#8: Am group because its Interquartile gruop is smaller than the Pm group

Step-by-step explanation:

Mark as Brainliest

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