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gayaneshka [121]
3 years ago
6

Can someone help I think I know the answer but I have one more time to get it wrong

Mathematics
2 answers:
zvonat [6]3 years ago
8 0

Answer:

23+(6x+1)=90 is the equation

Step-by-step explanation:

dimulka [17.4K]3 years ago
3 0

Answer:

6x+24 = 90

x=11

Step-by-step explanation:

6x+1+23 = 90

=> 6x+24 = 90

6x = 66

x= 11

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A video game is on sale for 25% off the original price is 42 what is the discount what is the sale price
Lynna [10]
$31.5, because that's the answer.
5 0
4 years ago
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The attendance at a seminar in year 1 was 500. In year 2, the attendance changed by 100. What was the percent change in attendan
Citrus2011 [14]

Answer:

20%

Step-by-step explanation:

to figure this out yourself you could simply do 100/500 = 0.2 which translates to 20%

3 0
3 years ago
Wendy is a math tutor. She charges $45 for each tutoring session plus $0.80 per mile that she has to drive to and from the sessi
omeli [17]

Answer:

equation:

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5 0
4 years ago
I have this calculus problem that I’m having trouble with. I’m not allowed to use the power rule. I need to use the formula s’(t
qaws [65]

Step-by-step explanation:

Know that

The derivative of position with respect of t is velocity.

Or if you want to say

\frac{d}{dt} (s(t) = v

Or in the form of the definition of the derivative

s'(t) =  \frac{6 (t + h) {}^{3} + 2(t + h)   + 9 - (6 {t}^{3} + 2t + 9) }{h}

s'(t) =  \frac{6 {t}^{3}  + 18t {}^{2}h + 18h {}^{2}  t + 6 {h}^{3}  + 2t + 2h + 9 - (6 {t}^{3}   +  2t + 9)}{h}

s'(t) =  \frac{18 {t}^{2}h + 18h {}^{2}t + 6h {}^{3}   + 2h }{h}

s'(t) = 18 {t}^{2}  + 18th + 6h {}^{2}  + 2

Let h be a small number, so we can cancel out small things.

s'(t) = 18 {t}^{2}  + 2

We know the derivative of position is velocity

v = 18 {t}^{2}  + 2

So the velocity at time t is

v = 18 {t}^{2}  + 2

Plug in 3 for t to find the velocity

v(3) =18(3) {}^{2}   + 2

v(3) = 164

So the velocity at t=3, is 164.

Next, the derivative of velocity is acceleration so

v'(t) =  \frac{18(t + h) {}^{2}  + 2 - (18 {t}^{2}  + 2)}{h}

v'(t) =  \frac{18 {t}^{2} + 36ht + 18 {h}^{2}  + 2(- 18 {t}^{2} + 2  ) }{h}

v'(t) =  \frac{36ht + 18 {h}^{2} }{h}

Divide by h.

v'(t) = 36t + 18h

v'(t) = 36t

The derivative of velocity is acceleration so

a = 36t

The acceleration in time t is

36t

To find acceleration, plug in 3 for t.

a(3) = 36( 3) = 108

4 0
3 years ago
Write in simplest form:<br> 4 1/3 : 7
Sedbober [7]

Answer:

13:21

Step-by-step explanation:

Change it into an improper fraction

13/3:7

Multiply 3 with 7

13:21

6 0
3 years ago
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