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Katyanochek1 [597]
3 years ago
8

Please help!

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
7 0

Answer:

number less than 3=1 and 2

so 2/6 = 1/3 in lowest terms

then rolling a 6 =

there is only one 6 so it will be 1/6

I hope I helped

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Separate the number 41 and the two parts so that the first number is eight more than twice the second number what are the two nu
vesna_86 [32]

The two numbers are 30 and 11

<em><u>Solution:</u></em>

Given that we have to separate the number 41 into two parts

Let the second number be "x"

<em><u>Given that first number is eight more than twice the second number</u></em>

first number = eight more than twice the second number

first number = 8 + twice the "x"

first number = 8 + 2x

So we can say first number added with second number ends up in 41

first number + second number = 41

8 + 2x + x = 41

8 + 3x = 41

3x = 41 - 8

3x = 33

x = 11

first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30

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3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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So 5^2 -4^2 is 25-16 which is 9
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I know that's the answer

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