The projectile's horizontal and vertical positions at time
are given by


where
. Solve
for the time
it takes for the projectile to reach the ground:

In this time, the projectile will have traveled horizontally a distance of

The projectile's horizontal and vertical velocities are given by


At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about
.
Answer:
The answer is 12a^3+2a²+23a+18 ....
Step-by-step explanation:
The given terms are:
(3a + 2)(4a² - 2a + 9)
Now multiply each value of second bracket with the first bracket:
=4a²(3a+2) -2a(3a+2)+9(3a+2)
=12a^3+8a²-6a²-4a+27a+18
Solve the like terms:
=12a^3+2a²+23a+18
Therefore the answer is 12a^3+2a²+23a+18 ....
Answer:
40
Step-by-step explanation:
2+2 = 4
4+4 = 8
8+32= 40
...................it is 1 pound .......................
Answer:
50
Step-by-step explanation:
you break the number up into pieces that fit each problem