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Brrunno [24]
3 years ago
6

Pls help!!!!!! I need the answer as fast as possible ​

Mathematics
1 answer:
klasskru [66]3 years ago
7 0

Answer:

6

Step-by-step explanation:

37-13 is 24.

One fourth of 24 is 6.

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H^-16/h^x=1/h^24 can someone help me please
Basile [38]

Given:

Consider the equation is

\dfrac{h^{16}}{h^x}=\dfrac{1}{h^{24}}

To find:

The value of x.

Solution:

We have,

\dfrac{h^{-16}}{h^x}=\dfrac{1}{h^{24}}

Using properties of exponents, we get

h^{-16-x}=h^{-24}       [\because \dfrac{a^m}{a^n}=a^{m-n},a^{-n}=\dfrac{1}{a^n}]

On comparing both sides, we get

-16-x=-24

Add 16 on both sides.

-x=-24+16

-x=-8

Multiply both sides by -1.

x=8

Therefore, the value of x is 8.

5 0
3 years ago
This is the 6th time i've asked this question. i'm so desperate, please help me!
OverLord2011 [107]

Answer:

Look at explanation.

Step-by-step explanation:

For the first four, take the first term and add the common difference to it to get the second term. Then add the common difference to the second term to get the third term, and so on until the 5th term. If the common difference is negative, you subtract it instead of adding it.

4 0
3 years ago
What is 9:81 in simplest form
Vsevolod [243]
9:81
=1:9

hope it helps u
3 0
3 years ago
The square of the sum of a number and 3 is 16. Find the number.(There are two solutions.)
iren2701 [21]
1,-7 hope this helps
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Read 2 more answers
NAND"" and ""NOR"" circuits are commonly used as a basis for flash memory chips. A NAND B is defined to be the negation of ""A a
Anit [1.1K]

Answer:

(i) A truth table shows how the truth or falsity of a compound statement depends on the truth or falsity of the simple statements from which it's constructed.

Since A ∧ B (the symbol ∧ means A and B) is true only when both A and B are true, its negation A NAND B is true as long as one of A or B is false.

Since A ∨ B (the symbol ∨ means A or B) is true when one of A or B is true, its negation A NOR B is only true when both A and B are false.

Below are the truth tables for NAND and NOR connectives.

(ii) To show that (A NAND B)∨(A NOR B) is equivalent to (A NAND B) we build the truth table.

Since the last column (A NAND B)∨(A NOR B) is equal to (A NAND B) it follows that the statements are equivalent.

(iii) To show that (A NAND B)∧(A NOR B) is equivalent to (A NOR B) we build the truth table.

Since the last column (A NAND B)∧(A NOR B) is equal to (A NOR B) it follows that the statements are equivalent.

6 0
3 years ago
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