Question

PLEASE HELP! AND PLEASE EXPLAIN HOW YOU SOLVED

Answer 1

Step-by-step explanation:

The height of the ball is given by

$h = -16t^2 + 144t + 5$

We can solve for the time when it reaches the height of 325 feet as follows:

$325 = -16t^2 + 144t + 5 \\ \Rightarrow 16t^2 - 144t + 320=0$

To solve this equation, we use the quadratic formula:

$t = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2s}$

$\:\:\:\:= \dfrac{144 \pm \sqrt{(-144)^2 - 4(16)(320)}}{32}$

$\:\:\:\:=\dfrac{144 \pm 16}{32} = 4\:\text{s},\:5\:\text{s}$

So this means that the ball will reach the height of 325 ft four seconds after launch, continue going up and a second later, it will at the height of 325 ft on it way down.