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malfutka [58]
3 years ago
12

Which fraction and decimal forms match the long division problem?

Mathematics
1 answer:
kolbaska11 [484]3 years ago
4 0

Answer:

Option B and D .....

If the provide option is correct

Or else it should be 7/9 and 0.777

mark me as brainliest ❤️

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Solve for x: −3|2x 6| = −12 x = 1 and x = 5 x = −1 and x = −5 x = −9 and x = 3 no solution
Kruka [31]
-3|2x + 6| = -12
|2x + 6| = -12/-3 = 4
2x + 6 = 4 and 2x + 6 = -4
2x = 4 - 6 and 2x = -4 - 6
2x = -2 and 2x = -10
x = -2/2 and x = -10/2
x = -1 and x = -5
5 0
4 years ago
Can someone plz help me with this one problem!!!
Sladkaya [172]

Answer:

No

Step-by-step explanation:

The first coordinate is x and the second is y so that makes the equation 3=6 which is not true.

5 0
3 years ago
Read 2 more answers
Applying Integer Operations
xeze [42]
-9 yards

5 sets of 3 yards

minus

2 sets of 12 yards

= -9
4 0
3 years ago
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The graph of g(x) is the result of translating the graph of f(x) = three units to the left. What is the equation of g(x)?
jenyasd209 [6]
In the case of exponential functions, the graph is shifted when a constant is added to the exponent of the constant. The original equation, f(x) is:
f(x) = (1/2)ˣ
Now, when horizontal shifting is occurring, the equation is:
y = Cˣ⁺ᵃ
If a is positive, the graph shifts to the lefts and the shift is equal to a units. If a is negative, the graph shifts to the right and the shift is equal to a units. Therefore, to shift the graph 3 units to the left:

g(x) = (1/2)⁽ˣ⁺³⁾
The correct answer is B.
3 0
3 years ago
Read 2 more answers
Find dw/ds using the appropriate Chain Rule for w=y^3-4x^2y where x=e^s and y=e^t, and evaluate the partial derivative at s=-3 a
Bad White [126]

Answer:

-2.95

Step-by-step explanation:

Given the functions w=y^3-4x^2y where x=e^s and y=e^t, to get dw/ds, we will use the chain rule for composite functions as shown;

dw/ds = dw/dx*dx/ds + dw/dy*dy/ds

dw/dx = -8xy

dx/ds = e^s

dw/dy = 3y²-4x²

dy/ds = 0 (since there are no s variable in the function)

Substituting the differentials into the formula above;

dw/ds = -8xy(e^s) + 3y²-4x²(0)

dw/ds = -8xy(e^s)

Substituting s = -3 and t = 5 into the resulting function;

dw/ds = -8(e^s)(e^t)(e^s)

dw/ds = -8(e^2s)(e^t)

dw/ds =  -8(e^-6)(e^5)

dw/ds = -8*0.00248*148.413

dw/ds = -2.945 ≈ --2.95 (to 2 dp)

4 0
3 years ago
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