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maks197457 [2]
3 years ago
7

Solve for x.A. x =9B. x = 3C. x = 4D. x = 27

Mathematics
1 answer:
meriva3 years ago
8 0
Your formula for this is 9^{2} =x(24+x) and 81=24x+ x^{2}.  Get everything on one side of the equals sign, set it equal to 0 and factor.  When you do this you get (x-3)(x+27). The Zero Product Property rule tells us that either x-3 = 0 or x+27 = 0 and that x = 3 and -27.  The only thing in math that will NEVER be negative besides time is distance/length, therefore, x cannot be 27 and has to be 3.
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Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.
Hitman42 [59]
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sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
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sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
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tan(\theta)=\cfrac{opposite}{adjacent}\\\\
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\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
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sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
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\textit{using the pythagorean theorem}\\\\
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7 0
3 years ago
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Phantasy [73]

Answer:

33.08 m

Step-by-step explanation:

angle of ∆ = 131.6 - 90 = 41.6

=> x² = 8²+3²-2(8)(3)cos 41.6°

= 64+9-48(0.75)

= 73 - 36

= 37

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perimeter = (3×8)+3+6.08 = 33.08 m

5 0
2 years ago
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Aliun [14]

Explanation:

x + 3y = 2

<u>Converting it to slope intercept form</u>:

y = mx + b  [where m is slope, b is y-intercept]

<u>Make y the subject</u>:

\sf \rightarrow  3y = 2 - x

\sf \rightarrow 3y = -x + 2

\sf \rightarrow y = -\dfrac{x}{3} + \dfrac{2}{3}

\sf \rightarrow y = -\dfrac{1}{3} x+ \dfrac{2}{3}

<u>which reveals slope</u>:

\star \   slope: \sf  - \dfrac{1}{3}

7 0
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