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maks197457 [2]
4 years ago
7

Solve for x.A. x =9B. x = 3C. x = 4D. x = 27

Mathematics
1 answer:
meriva4 years ago
8 0
Your formula for this is 9^{2} =x(24+x) and 81=24x+ x^{2}.  Get everything on one side of the equals sign, set it equal to 0 and factor.  When you do this you get (x-3)(x+27). The Zero Product Property rule tells us that either x-3 = 0 or x+27 = 0 and that x = 3 and -27.  The only thing in math that will NEVER be negative besides time is distance/length, therefore, x cannot be 27 and has to be 3.
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