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AveGali [126]
2 years ago
7

Can you help me plz

Mathematics
1 answer:
Alex73 [517]2 years ago
6 0

9514 1404 393

Answer:

  y = x + 4

Step-by-step explanation:

To find the constant in the equation, look in the table for the value of y when x=0. That value is 4, so ...

  y = x + 4

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Find the zeros of the quadratic function: y= 6(7x + 9)(8x - 3).
fiasKO [112]

Answer:

A) (-9/7,0), (3/8,0)

Step-by-step explanation:

Zeros of a quadratic function:

x for which y = 0.

In this question:

y = 6(7x + 9)(8x - 3)

It's 0 if one of the factors is 0. 6 is never 0, now about the other to:

7x + 9 = 0

7x = -9

x = -\frac{9}{7}

So (-9/7, 0) is a zero of the quadratic function.

The other is:

8x - 3 = 0

8x = 3

x = \frac{3}{8}

(3/8,0) is the other zero.

Thus, the correct answer is given by option A.

6 0
2 years ago
BRAINLIEST ANSWER FOR FIRST Please help with the problem below
Sidana [21]
Answer:

m\:]

Step-by-step explanation:

The given inequality is ;

\frac{2m+3}{2}-\frac{17}{4}\:

Multiply through by 8 to clear the fraction;

4(2m+3)-2(17)\:

Expand;

8m+12-34\:

Group similar terms;

8m-m\:

7m\:

m\:
7 0
3 years ago
Read 2 more answers
If f(x)= 3x squares +1 and g(x) =1-x what is the value of (f-g)(2)
ZanzabumX [31]

Answer: (f-g)(2)=14

Step-by-step explanation:

(f – g) (-2) means the same as subtracting f(2) and g(2). Since we are given f(x) and g(x), we can use them to solve. There are two ways to solve. One is to find f(2) and g(2), and then subtract them. Another way is to do (f-g)(x), then plug in x=2. I will show both methods.

Method 1

f(2)=3(2)²+1                                [exponent]

f(2)=3(4)+1                                  [multiply]

f(2)=12+1                                     [add]

f(2)=13

g(2)=1-(2)                                    [subtract]

g(2)=-1                  

(f-g)(2)=13-(-1)                            [subtract f(2) and g(2)]

(f-g)(2)=14

--------------------------------------------------------------------------------------------------------

Method 2

(f-g)(x)=3x²+1-(1-x)                     [distribute -1]

(f-g)(x)=3x²+1-1+x                      [combine like terms]

(f-g)(x)=3x²+x

(f-g)(2)=3(2)²+2                         [plug in x=2, exponent]

(f-g)(2)=3(4)+2                           [multiply]

(f-g)(2)=12+2                             [add]

(f-g)(2)=14

--------------------------------------------------------------------------------------------------------

Now, we know that (f-g)(2)=14. We confirmed this with both methods.

8 0
3 years ago
If the ratio of a circle's sector to its total area is 3/8, what is the measure of its sector's arc?
mars1129 [50]
Imagine the area is 360 degrees, or 2\pi radians.

You would multiply it by (3/8) to get your answer.
6 0
3 years ago
Read 2 more answers
What is true about a function?
mars1129 [50]

Answer: Your answer is the third one, a function assigns to each input exactly one output.

If you have a true function, there will only be one output for each input, if you had more than one, it isn't a function.


6 0
3 years ago
Read 2 more answers
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