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trapecia [35]
3 years ago
12

A boy rolls down a hill on a skateboard. At time = 4 seconds, that boy has rolled 6 meters from the top of the hill. At time = 7

seconds, the boy has rolled to a distance of 30 meters. What is his average speed?
Mathematics
1 answer:
spayn [35]3 years ago
3 0

Answer:

His average speed is 4.75 m/s

Step-by-step explanation:

Here, we are interested in calculating the average speed of the boy.

At time t = 4 seconds, total distance traveled = 6 meters

The average speed here is distance/time = 6/4 = 1.5 m/s

Now at time 30 7 seconds , he has rolled 30 meters

What this actually means is that for the next 3 seconds after the initial 4 seconds, he rolled a total distance of 30-6 = 24 meters. Hence, he rolled 24 meters in the next three seconds

So mathematically, his average speed for the second part of the rolling is 24/3 = 8 meters per second

Conclusively therefore , his average speed will be (1.5 + 8)/2 = 9.5/2 = 4.75 meters per second

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A space telescope on a mountaintop is housed inside of a cylindrical building with a hemispheric dome. If the circumference of t
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Answer:

 185553.7\text{ feet}^3

Step-by-step explanation:

GIVEN: A space telescope on a mountaintop is housed inside of a cylindrical building with a hemispheric dome. If the circumference of the dome is 84\text{ feet}, and the total height of the building up to the top of the dome is 91\text{ feet}.

TO FIND: what is the approximate total volume of the building.

SOLUTION:

let the height of the mountaintop be h\text{ feet}

As the dome hemispherical.

circumference of a hemisphere =\frac{1}{2}\times2\pi\times radius

                                                    =\pi\times radius

                                                    \frac{22}{7}\times radius=84

                                                    radius=26.75\text{ feet}

total height of the building up to the top of the dome =\text{radius of hemisphere}+\text{height of mountaintop}

=26.75+h=91

h=64.25\text{ feet}

Volume of building =\text{volume of cylindrical mountaintop}+\text{volume of dome}

                                =\pi(radius)^2h+\frac{2}{3}\pi(radius)^3

as radius of mountain top is same as dome

putting values

                                =3.14(26.75)^264.75+\frac{2}{3}3.14(26.75)^3      

                               =145484.6+40069.1

                               185553.7\text{ feet}^3

Hence the total volume of the building is 185553.7\text{ feet}^3                                      

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