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Kisachek [45]
3 years ago
5

Beau has decided to use the method of elimination to solve the system of equations as shown below.

Mathematics
1 answer:
nydimaria [60]3 years ago
4 0

Answer:

Step-by-step explanation:

Usually when we solve using elimination we have to multiply one equation by a certain number so that when we add them together one term will cancel with another. Here its already done for us. So, the first step that Beau should do in this case, is to add the two equations together so that -3y and +3y will cancel out and become 0. That leaves us with this- being an equation we can solve: 3x = 18. The technique of using elimination is useful because by manipulating one equation so that one variable term (meaning a term with x and y) will cancel with another we can have an equation with only one variable that we can solve. After solving that equation we can then plug that value back into one of the original equations and then solve for the other value, in this case the value for y.

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BartSMP [9]

Answer:

B

Step-by-step explanation:

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2 years ago
What is 7/12 as a decimal<br><br> Please help ASAP
svlad2 [7]

Answer:

\frac{7}{12} = 0.583333333...

Step-by-step explanation:

To write \frac{7}{12} as a decimal.

Decimal defined as the number with a decimal point in it.

also, the decimal  point separates part of whole number and the fractional part in the decimal numbers.

To turn this fraction into a decimal number,

all you have to do is to divide the top number by bottom number i.e

\frac{7}{12} = 7 \div 12

\frac{7}{12} = 0.583333333...

Therefore, 7/12 as a decimal is, 0.583333333....

4 0
3 years ago
Find the real or imaginary solutions of each equation by factoring
anyanavicka [17]
Sum of  2 perfect cubes
a³+b³=(a+b)(x²-xy+y²)
so

x³+4³=(x+4)(x²-4x+16)
set each to zero
x+4=0
x=-4

the other one can't be solveed using conventional means
use quadratic formula
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}
for x²-4x+16=0
x=\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(16)} }{2(1)}
x=\frac{4+/- \sqrt{16-64} }{2}
x=\frac{4+/- \sqrt{-48} }{2}
x=\frac{4+/- (\sqrt{-1})(\sqrt{48}) }{2}
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the roots are
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8 0
3 years ago
4/9(x + 13) = 8 what is the value of the x ​
allochka39001 [22]

Answer:

x=5

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Let n1equals50​, Upper X 1equals30​, n2equals50​, and Upper X 2equals10. Complete parts​ (a) and​ (b) below. a. At the 0.05 leve
Viefleur [7K]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.

Step-by-step explanation:

1) Data given and notation  

X_{1}=30 represent the number of people with a characteristic in 1

X_{2}=10 represent the number of people with a characteristic in 2

n_{1}=50 sample of 1 selected  

n_{2}=50 sample of 2 selected  

p_{1}=\frac{30}{50}=0.6 represent the proportion of people with a characteristic in 1

p_{2}=\frac{10}{50}=0.2 represent the proportion of people with a characteristic in 2

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion 1 is different from proportion 2 , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{30+10}{50+50}=0.4  

3) Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.  

3 0
3 years ago
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