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Arada [10]
2 years ago
10

Do your best i need it quickly sorta, if you do a weird answer just for the points i will report you.

Mathematics
2 answers:
solong [7]2 years ago
7 0

Answer: See below

Step-by-step explanation:

For this problem, we are given four functions, and their domains. All we have to do is figure out which equation we want to plug x into and solve.

f(-20)

For this first problem, we have x=-20. Then we can eliminate equations 1, 2, 4. We know equation 3 is the correct one because it says x<-12. -20 is less than -12. Therefore we plug in x=-20 to the third equation.

f(-20)=3(-20)-7              [multiply]

f(-20)=-60-7                  [subtract]

f(-20)=-67

--------------------------------------------------------------------------------------------

f(0)

For this problem, we have x=0. Then we can eliminate equations 1, 2, 3. We know equation 4 is the correct one because it says x∈{-15, -12, 0, 10}. This means x has to be either one of the four numbers listed in the parentheses. We see that x=0 is in there. Therefore we plug in x=0 to the fourth equation.

f(0)=11-|-0-1|             [subtract]

f(0)=11-|-1|                [absolute value]

f(0)=11-1                    [subtract]

f(0)=10

--------------------------------------------------------------------------------------------

f(15)

For this problem, we have x=15. Then we can eliminate equations 2, 3, 4. We know equation 1 is the correct one because it says x>10. This means x has to be greater than 10. 15 is greater than 10. Therefore we plug in x=15 to the first equation.

f(15)=\frac{1}{|15+1|-11}       [add]

f(15)=\frac{1}{|16|-11}           [absolute value]

f(15)=\frac{1}{16-11}             [subtract]

f(15)=\frac{1}{5}

anastassius [24]2 years ago
7 0

For f(-20), you start by determining which of the pieces the x-value of -20 fits into.

Wow, those are some convoluted conditions on the right.  

Note: I originally had this post with using x = 20 and not x = -20.  The rest of this has been corrected to reflect that change.

Eventually you see "x<-20" on the third line/third piece of the function.  So that tells you that you need to use the third piece and for x=-20, just treat the function as is it was

    f(x) = 3x-7

This means,

    f(-20) = 3(-20)-7

Can you finish that out from there?

Recap:

Step #1: figure out which piece your x-value fits with.

Step #2: plug in the x-value into that piece and evaluate it.

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PLEASE HELP AND SHOW ALL STEPS
Alja [10]

Combining the like terms, the simplified polynomials are given as follows:

a) 4x² - 14x + 17

b) -5x² - 20x + 8

<h3>How are polynomials simplified?</h3>

Polynomials are simplified combining the like terms, that is, adding these numbers with the same variable.

Item a:

4(x - 2)(x + 1) - 5(2x - 5)

Applying the distributive property:

4(x² - x - 2) - 10x + 25

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Combining the like terms:

4x² - 4x - 10x - 8 + 25

4x² - 14x + 17

Item b:

-5(x + 2)² + 28

-5(x² + 4x + 4) + 28

-5x² - 20x - 20 + 28

-5x² - 20x + 8

More can be learned about the simplification of polynomials at brainly.com/question/24450834

#SPJ1

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Step-by-step explanation:

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Read 2 more answers
How many solutions does the equation have? a+5=1/5(5a+25)
Iteru [2.4K]
A + 5 = \frac{1}{5} (5a + 25)

First, simplify \frac{1}{5} (5a + 25) to \frac{5a+25}{5} / Your problem should look like: a + 5 =  \frac{5a+25}{5}
Second, multiply both sides by 5. / Your problem should look like: 5a + 25 = 5(a + 5)
Third, expand to get rid of parenthesis. / Your problem should look like: 5a + 25 = 5a + 25
Fourth, both sides are equal, resulting it having infinite solutions.

Answer: infinite solutions

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