Answer:
Mr. Smith is not justified, Mrs. Smith can not be blamed necessarily for being unfaithful
Explanation:
Widow's peak is a dominant trait which means that it will be expressed both in homozygous and heterozygous condition. If "A" is the dominant allele and "a" is the recessive allele, the trait can be represented as AA or Aa.
Both Mr. Smith and Mrs. smith expressed the trait so they can either have AA or Aa genotype. If even one of them had AA genotype all the offspring would have the trait. But if both of them are heterozygous for it:
A a
A AA Aa
a Aa aa
There is 75 % probability of the child to have the trait (AA or Aa) but there is also 25% probability that the child does not express the trait (aa). Their second child belongs to this category and hence Mrs. Smith can not be blamed for being unfaithful.
Answer: A) The endometrial lining is shed in menstrual cycles but reabsorbed in estrous cycles.
Explanation:
The endometrium can be defined as the inner layer of the epithelium. It along with the mucous membrane forms the covering of the mammalian uterus. It is the basal and functional layer of the uterus. This layer thickens and then shed during the menstruation cycle in humans and in some other mammals including the apes, monkeys, bats and elephants. But the endometrium layer is reabsorbed in the estrous cycle.
Answer:
The correct answer is C. the one who prioritizes tasks and then starts work.
Explanation:
In order to be a good manager and to achieve great results, one should always calculate the priority of each task and then start working on it (beginning with the most important task first). The response A. is not correct because working that way a manager would miss to do first the urgent and important tasks. The answers B. and C. are very subjective. What we consider pleasant or unpleasant is up to every individual. Also the category of something being pleasant or unpleasant doesn´t have a lot to do with productivity.
