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jonny [76]
3 years ago
13

Solve: Four young women went on nature walk. Before long, each of them spotted a beautiful bird, although no two spotted the sam

e bird. From the clues below, find the clues below, find each woman's full name and which bird she saw. Neither Lilly nor Mrs. Halliday has ever seen an indigo bunting
Pamela who has never married was right behind the person who saw the cardinal and the one who spotted the indigo bunting Ms. Wellington and Karen ahead of the others neither of them saw the oriole. Grace was behind Ms. Baker Lilly and the woman who saw the scarlet tanager. Miss Isaacs and Miss Baker both heard the oriole but they couldn't see it.
Mathematics
1 answer:
user100 [1]3 years ago
7 0

Answer:

  • Lily Wellington saw the Cardinal
  • Karen Baker saw the Indigo Bunting
  • Pamela Isaacs saw the Scarlet Tanager
  • Grace Halliday saw the Oriole

Step-by-step explation:

In addition to the name clues, the order clues (ahead/behind) are also helpful. The above answers are listed in order, with Lily (or Karen) being first and Grace being last.

The only "Miss" in the group is Miss Isaacs, so Pamela, who has never married, must be Pamela Isaacs. Grace was behind 3 women, so must be last. Miss Isaacs did not see the oriole, nor the cardinal or indigo bunting, so must have seen the scarlet tanager.

The women who saw the cardinal and indigo bunting were the first two, so Grace saw the oriole. She was not Ms Baker or Ms Wellington, so must have been Grace Halliday.

Karen was not Ms Wellington, so must have been Ms Baker. Then Lily was Ms Wellington. She had not seen an indigo bunting, so Lily Wellington saw the cardinal, and Karen Baker saw the indigo bunting.

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

P=2l+2w

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Step-by-step explanation:

\frac{3}{4}b=8

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Kamila [148]
<h2><u>Diagram</u><u>:</u><u>-</u></h2>

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<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

The diagonals of the Rhombus= d1 & d2=6cm and 8cm

Let the Side=a

As we know that in a Rhombus

{\boxed{\sf side=\sqrt {\left ({\dfrac{d1}{2}}\right)^2+\left ({\dfrac {d2}{2}}\right)^2}}}

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{:}\longmapsto\sf a=\sqrt {\left ({\dfrac {6}{2}}\right)^2+\left ({\dfrac {8}{2}}\right)^2 }

{:}\longmapsto\sf a=\sqrt {(3)^2+(4)^2}

{:}\longmapsto\sf a=\sqrt {9+16}

{:}\longmapsto\sf a=\sqrt{25}

{:}\longmapsto\sf a=5cm

<h2>_____________</h2><h3>Again </h3>

we know that in a Rhombus

\boxed{\sf Perimeter=4a}

  • Substitute the values

{:}\longmapsto\sf Perimeter=4×5

{:}\longmapsto\sf Perimeter=20cm

\thereforePerimeter of the rectangle is 20cm.

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Step-by-step explanation:



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