Testing the hypothesis, it is found that since the p-value of the test is of 0.3015, which is greater than the significance level of 0.05, the data does not provide enough evidence to show that Alaska had a lower proportion of identity theft than 23%.
At the null hypothesis, we <u>test if the proportion is of 23%</u>, that is:

At the alternative hypothesis, we <u>test if this proportion is lower than 23%</u>, that is:

The test statistic is given by:
In which:
is the sample proportion.
- p is the proportion tested at the null hypothesis.
- n is the sample size.
In this problem, the parameters are: 
Then, the value of the <u>test statistic</u> is:



The p-value of the test is the probability of finding a sample proportion of 0.2242 or below, which is the <u>p-value of z = -0.52</u>.
- Looking at the z-table, z = -0.52 has a p-value of 0.3015.
Since the p-value of the test is of 0.3015, which is greater than the significance level of 0.05, the data does not provide enough evidence to show that Alaska had a lower proportion of identity theft than 23%.
A similar problem is given at brainly.com/question/14639462