Answer:
you can see when you put x = -3 you get 0 for g(x)
so we can write g(x) = 3+x because if we put x to be -3 in this equation you get 0.
a. h(0) = f(0)g(0), g(0) = 3+0= 3
h(0) = f(0)x3, now In the graph f(x) we can see at x=0, y is -1.
now h(0) = -1x3 = -3 (answer)
b. (-infinity, +infinity) or (-2, inf) I'm not sure.
c. values that yeild h(x)=0 are; -3, 3, -1.
