The events are dependent.
When the first card is not replaced, you change the probability of the second card. At the very least, you have changed the total number of cards to draw from.
Area = 1/2 x (a+b) x h
= 1/2 x ( 5+ 13) x 17
=1/2 x 18 x 17
= 153cm.
(a and b are the two parallel lines. H is height.)
Answer:
Third one? I'm not sure though.
Step-by-step explanation:
Answer:
y = - 16t² + 55.6t + 6
Step-by-step explanation:
Using y - y₀ = vt - 1/2gt² where g = 32 ft/s², and v the velocity of the football
So y = y₀ + vt - 1/2 × (32 ft/s²)t²
y = y₀ + vt - 16t² where y₀ = 6.5 ft
y = 6 + vt - 16t²
Now, when t = 3.5 s, that is the time the teammate catches the ball after the quarterback throws it, y = 5 ft. Substituting these into the equation, we have
5 = 6.5 + v(3.5 s) - 16(3.5 s)²
5 = 6.5 + 3.5v - 196
collecting like terms, we have
5 - 6.5 + 196 = 3.5v
194.5 = 3.5v
v = 194.5/3.5 = 55.57 ft/s ≅ 55.6 ft/s
So, substituting v into y, our quadratic model is
y = 6 + 55.6t - 16t²
re-arranging, we have
y = - 16t² + 55.6t + 6
Answer:
374.1
Step-by-step explanation:
Area of Hexagon = 
The ' a ' is the side length.
So now we just plug in the values
= 374.12
