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Aleksandr-060686 [28]
3 years ago
8

What are the unit rates for  4/8 , 5/25, 36/6, 14/21, 18/30, 28/16, 56/35, 45/108, 12/42, 39/26

Mathematics
2 answers:
AlexFokin [52]3 years ago
6 0

Answer:

i also needhelp on this one

Step-by-step explanation:

DIA [1.3K]3 years ago
4 0
Unit rates is same as nominator in this case it will be:
4,5,36,14,18,28,56,45,12,39
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Let x and y be real numbers satisfying 2/x=y/3=x/y Determine the value of x^3
svet-max [94.6K]

Answer:

<h2>64/27</h2>

Step-by-step explanation:

If  x and y be real numbers satisfying 2/x=y/3=x/y, then any two of the equation are equated as shown;

2/x = y/3 ... 1 and;

y/3 = x/y... 2

From equation 1, 2y = 3x ... 3

and from equation 2; y² = 3x ... 4

Equating the left hand side of equation 3 and 4 since their right hand sides are equal, we will have;

2y = y²

2 = y

y = 2

Substituting y = 2 into equation 3 to get the value of x;

2y = 3x

2(2) = 3x

4 = 3x

x = 4/3

The value of x³ will be expressed as (4/3)³ = 4*4*4/3*3*3 = 64/27

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3 years ago
Stu wants to join a gym. Fit-Place charges a $135 startup fee and then $35 per month. The Factory has no startup fee but charges
antiseptic1488 [7]

I don't know the answer use a calculater

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3 years ago
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In preparation for a conference, Toby is setting up some stations where people can create
spin [16.1K]

Answer:

9

Step-by-step explanation:

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5 0
3 years ago
Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).
storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

5 0
3 years ago
Rectangular apartments are 12 ft longer than they are wide. Each apartment has 1,053 ft^2 of floor space. What are the dimension
sashaice [31]
Can i just have points pls
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3 years ago
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