Answer:
2(4x + 1)(x + 1)
Step-by-step explanation:
Given
8x² + 10x + 2 ← factor out 2 from each term
= 2(4x² + 5x + 1)
To factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 4 × 1 = 4 and sum = + 5
The factors are + 1 and + 4
Use these factors to split the x - term
4x² + x + 4x + 1 ( factor the first/second and third/fourth terms )
= x(4x + 1) + 1 (4x + 1) ← factor out (4x + 1)
= (4x + 1)(x + 1), thus
4x² + 5x + 1 = (4x + 1)(x + 1) and
8x² + 10x + 2 = 2(4x + 1)(x + 1) ← in factored form
I think B because I think B
Because AB is a midsegment, the length of AB is half he length of XZ so basically you do
2(3x-1)=34.
Divide 2 by both sides to get 3X-1=17
Add 1 to boh sides to get 3X=18
Divide 3 from boh sides to get X=6
Hope this helps :)
True I’m not sure I’m just guessing cause I gotta answer Two questions before mine
