Please I want an before 2:00

Mathematics

1 answer:

Snezhnost [94]3 years ago

6 0

Here's a photo of the solution. Hope it helps and please give brainlist!

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Anyone know how to do this ? If so can u help me ? Thanks <3

kramer

Answer:

24.1 x 10^4 = 241000 .056 x 10^7 = 560000 507 x 10^-5 = 0.00507

Step-by-step explanation:

for scientific notation, all you need to do is start at the decimal point (or end of whole number) and move over the amount of spaces (the exponent) to the right. if it is a negative exponent, instead of moving to the right, you should move to the left.

for example : 500 x 10^3

when you start from the last zero and move to the right, you need to fill the space with three zeroes.

so 500 x 10^3 = 500,000.

5 0

4 years ago

Help me please ITS DUE IN 6 MINS PLEASE

DerKrebs [107]

Answer: -6y-12 and 5.5h+14

Step-by-step explanation:

-2(3y+6) = -6y-12

5.1h-2.6h+3(h+4)= 2.5h + 3h+14 = 5.5h+14

6 0

3 years ago

In △ABC, point P∈ AC with AP:PC=1:3, point Q∈AB so that AQ:QB=3:4, Find the ratios APBQ : APBC and AAQP : AABC.

weqwewe [10]

Answer: The ratios APBQ : APBC=4:21 and AAQP : AABC= 3:28

Explanation:

Here, ABC is a triangle where, P and Q are the midpoints of the edges AC and AB respectively,

Now, according to the question ,AP:PC=1:3 let AP=x and PC=3x where x is any real number. Thus, AC=AP+AC= x+3x= 4x

Similarly, AQ:QB=3:4 let AQ=3y and QB=4y where y is also any real number. Thus, AB=AQ+QB=3y+4y=7y

Since, $\frac{AP.BQ}{AP.BC} =\frac{AP.BQ}{AB.PC} =\frac{x.4y}{7y.3x} =\frac{4xy}{21xy} =\frac{4}{21}$

And, $\frac{AA.QP}{AA.BC} =\frac{AQ.AP}{AB.AC} =\frac{3y.1x}{7y.4x} =\frac{3xy}{28xy} =\frac{3}{28}$

5 0

4 years ago

A keypad at the entrance of a building has 10 buttons labeled 0 through 9. What is the probability of a person correctly guessin

blondinia [14]

A keypad at the entrance of a building has 10 buttons labeled 0 through 9. What is the probability of a person correctly guessing a 9-digit entry code if they know that no digits repeat?

Answer:

the probability of a person correctly guessing a 9-digit entry code if they know that no digits repeat is 0.1

Step-by-step explanation:

We know that probability= number of required outcomes /number of all possible outcome.

From the given information;

the number of required outcome is guessing a 9-digit = 1 outcome

the number of all possible outcome = ¹⁰C₉ since there are 10 numbers and 9 number are to be selected.

Since there are only 9-digit that opens the lock;

the probability of a person correctly guessing a 9-digit entry code is

$P =\dfrac{1}{^{10}C_9}$