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blondinia [14]
3 years ago
5

Write. true or false​

Computers and Technology
2 answers:
ella [17]3 years ago
8 0
Um I need a image or smth
xz_007 [3.2K]3 years ago
7 0

Answer:

1 false

2 true

pliz mark me branliest pliz

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Please read !!!
prisoha [69]
Don’t stress. You’re no failure if you believe in yourself. Have some faith. Don’t give up and live your life to the fullest. Take care and stay safe!! :)
3 0
3 years ago
The Subset Sum problem is a generalization of the Knapsack problem. Group of answer choices True False g
Katarina [22]

Answer: True

Explanation:

Subset sum problem and Knapsack problem can be solved using dynamic programming.

In case of Knapsack problem there is a set of weights associative with objects and a set of profits associated with each object and a total capacity of knapsack let say C. With the help of dynamic programming we try to include object's weight such that total profit is maximized without fragmenting any weight of objects and without exceeding the capacity of knapsack, it is also called as 0/1 knapsack problem.

Similar to knapsack problem, in subset sum problem there is set of items and a set of weights associated with the items and a capacity let say C, task is to choose the subset of items such that total sum of weights associated with items of subset is maximized without exceeding the total capacity.

On the basis of above statements we can say that subset sum problem is generalization of knapsack problem.

4 0
3 years ago
How do I convert years to days on Python. For example, if I were to enter 3 years it should output "You are 1095 days old".
Scorpion4ik [409]

years = int(input("Enter the # of years: "))

print("You are "+str(years*365)+" days old")

I wrote the code in python 3.8. I hope this helps!

6 0
2 years ago
Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where
kozerog [31]

Answer:

  1. public class FindDuplicate{
  2.    public static void main(String[] args) {
  3.        Scanner input = new Scanner(System.in);
  4.        int n = 5;
  5.        int arr[] = new int[n];
  6.        for(int i=0; i < arr.length; i++){
  7.            int inputNum = input.nextInt();
  8.            if(inputNum >=1 && inputNum <=n) {
  9.                arr[i] = inputNum;
  10.            }
  11.        }
  12.        for(int j =0; j < arr.length; j++){
  13.            for(int k = 0; k < arr.length; k++){
  14.                if(j == k){
  15.                    continue;
  16.                }else{
  17.                    if(arr[j] == arr[k]){
  18.                        System.out.println("True");
  19.                        return;
  20.                    }
  21.                }
  22.            }
  23.        }
  24.        System.out.println("False");
  25.    }
  26. }

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

7 0
2 years ago
One interesting application of computers is to display graphs and bar charts. Write an application that reads five numbers betwe
Nezavi [6.7K]

Answer:

The answer to this question can be given by program that  are as follows

import java.util.*;

//import package for taking input from user.

public class Main   //define class

{

public static void main (String ag[] )   //define main function

{

 int number;

 Scanner input = new Scanner(System.in);

 for (int i = 0; i < 5; i ++)                       //loo for input.

 {

  System.out.print ("Enter a number between 1 - 30:  ");

  number = input.nextInt();          //input number by the user.

 

 }

 asterisk();           //calling function.

 }

public static void asterisk()          //defination of function.

{

    //body of function.

    int n;                   //local variable.

 for (n= 0; n <= 30; n++)                  //using loop for print asterisk

 {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );                  //print value.

 }

 

  for (n= 0; n <= 30; n++)         //using loop for print asterisk

  {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );     //print value.

 }

 

  for (n= 0; n <= 30; n++)          //using loop for print asterisk

  {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );          //print value.

 }

  for (n= 0; n <= 30; n++)            //using loop for print asterisk

 

 {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );               //print value.

 }

 

  for (n= 0; n <= 30; n++)             //using loop for print asterisk

  {

 if (n !=0)

 //printf used for print value.

 System.out.printf("*", n );             //print value.

 }

}

}

Output:

Enter a number between 1 - 30: 2

Enter a number between 1 - 30: 2

Enter a number between 1 - 30: 1  

Enter a number between 1 - 30: 3

Enter a number between 1 - 30: 4

*******************************************************************************

Explanation:

In this program we take 5 time input from the user and print the value in the form of (*) that can be explain in above output section.In that program we use printf method that is also used for print the value.

3 0
3 years ago
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