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3 years ago

Can you help me with these 3?

Mathematics

1 answer:

miskamm [114]3 years ago

3 0

Step-by-step explanation:

1. 5,11,17,23,29,35

Common difference is 6

3. 8,21,34, 47,60

Common difference is 13

5. 5,10,15,20,25

Common difference is 5

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tatuchka [14]

Your answer will be 406 hope this helps

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4 years ago

100 points!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! please help

FromTheMoon [43]

Answer:

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4 0

3 years ago

Read 2 more answers

1. Lenny cleans 75 cars in 5 days. At this rate, how many days will it take him to wash 90 cars? *please I need some help

Ahat [919]

Answer: 6 days

Explanation: If he washes 75 cars in 5 days; and you need to find how many days it takes to wash 90 you do 75 divided by 5 which is 15; so he washes 15 cars in a day, then do 90 divided by 15 which is 6 days

8 0

3 years ago

Suppose a population grows according to the logistic equation but is subject to a constant total harvest rate of H. If N(t) is t

Elenna [48]

Answer:

a) Equilibrium point : [ 947, 53 ]

b) N = 947 is stable equilibrium, N = 53 is unstable equilibrium

c) N0, the population will not go extinct

Step-by-step explanation:

Given that;

r = 2, k = 1000, H = 100

dN/dT = R(1 - N/k)N - H

so we substitute

dN/dt = 2( 1 - N/1000)N - 100

now for equilibrium solution, dN/dt = 0

2( 1 - N/1000)N - 100 = 0

((1000 - N)/1000)N = 50

N^2 - 1000N + 50000 = 0

N = 1000 ± √(-1000)² - 4(1)(50000)) / 2(1)

N = 947.213 OR 52.786

approximately

N = 947 OR 53

Therefore Equilibrium point : [ 947, 53 ]

g(N) = 2( 1 - N/1000)N - 100

= 2N - N²/500 - 100

g'(N) = 2 - N/250

SO AT 947

g'(N) = g'(947) = 2 - 947/250 = -1.788 which is less than (<) 0

so N = 947 is stable equilibrium

now AT 53

g'(N) = g"(53) = 2 - 53/250 = 1.788 which is greater than (>) 0

so N = 53 is unstable equilibrium

The capacity k=1000

If the population is less than 53 then the population will become extinct but since the capacity is equal to 1000 then the population will not go extinct.

6 0

3 years ago

Angus has $3,000 he want to invest. What interest rate compounded continuously does an account need to offer so that Angus has $

kaheart [24]

Answer:

The interest rate is 7.58%

Step-by-step explanation:

Compound continuous interest can be calculated using the formula:

A = P $e^{rt}$ , where

A is the future value of the investment, including interest

P is the principal investment amount (the initial amount)

r is the interest rate in decimal

t is the time the money is invested for

∵ Angus has $3,000 he want to invest

∴ P = 3000

∵ The interest rate is compounded continuously

∵ Angus has $5,500 in 8 years

∴ A = 5500

∴ t = 8

→ Substitute them in the rule above to find r

∵ 5500 = 3000 $e^{8r}$

→ Divide both sides by 3000

∴ $\frac{11}{6}$ = $e^{8r}$

→ Insert ㏑ in both sides

∵ ㏑( $\frac{11}{6}$ ) = ㏑( $e^{8r}$ )

→ Remember ㏑( $e^{n}$ ) = n

∴ ㏑( $\frac{11}{6}$ ) = 8r

→ Divide both sides by 8

∴ 0.07576697545 = r

→ Multiply it by 100% to change it to a percentage

∴ r = 0.07576697545 × 100%

∴ r = 7.576697545 %

→ Round it to the nearest hundredth

∴ r ≅ 7.58

∴ The interest rate is 7.58%

3 0

3 years ago