We’re going to start off simple so we’re not going to write the graph in point-slope form yet, but let’s practice how to write it in slope-intercept form.
Thus, the question is already giving us a slope, which is something needed.
Slope-Intercept Form: y = mx + b where m = slope
Now solve for b which it means for y-intercept.
The y-intercept is always located at the y-axis when x = 0. In this case, b = 2
Now let’s place the dimensions of what we have so far
y = -2x + 2
Then we’re going to use the point for point-slope form.
Point-Slope Form: y - y1 = m(x - x1)
To write the graph in point-slope form, use the Slope-intercept form to fill out the dimensions.
Slope-Intercept Form: y = -2x + 2
With the point: (4, -6)
“That means 4 = x1 and -6 = y1)
Point-Slope Form: y + 6 = -2(x - 4) •••••••••••••••••••••••••••••••••••••••••
Answered by: doomdabomb
*All brainliest answers are appreciated and would mean a lot to me*
