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3 years ago

Solve the quadratic equation using the square root property

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

8 0

Answer:

X=16.5

Step-by-step explanation:

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What is an equation of the line that passes through the point (3,-3) and is perpendicular to the line 3x+2y=12 ?

Gennadij [26K]

Answer:

y=2/3x-5

Step-by-step explanation:

1. find the slope of the given line

2. find its opposite reciprocal(slope of the perpendicular line)

3. create a new linear equation using the new slope

4. substitute (3,-3) to find b

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3 years ago

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What is the ratio 12/21 equivalent to

Amiraneli [1.4K]

4/7, because both the numerator and denominator can be divisible by 3.

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3 years ago

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Find the solution to the system of equations.<br> 1 + 3y = 4<br> 2r + 5y = 12

ivann1987 [24]

Answer: {x,y}={-1,2}

step-by-step explanation:

// Solve equation [2] for the variable x

[2] 2x = 5y - 12

[2] x = 5y/2 - 6

// Plug this in for variable x in equation [1]

[1] 2•(5y/2-6) + 3y = 4

[1] 8y = 16

// Solve equation [1] for the variable y

[1] 8y = 16

[1] y = 2

// By now we know this much :

x = 5y/2-6

y = 2

// Use the y value to solve for x

x = (5/2)(2)-6 = -1

Solution :

{x,y} = {-1,2}

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2 years ago

Roberto makes 35% of the shots he attempts in basketball. How many shots does he make if he attempts 20 shots?

kirill [66]

Answer:

Roberto makes 7 shots

Step-by-step explanation:

35% is 0.35 as a decimal. Multiply the decimal by the total amount of attempted shots.

20(0.35)=7

Roberto makes 7 shots.

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3 years ago

Which rule describes the composition of transformations that maps pre- image ABCD to final image A“B“C“D“?

Svetlanka [38]

Answer:

1. Reflection across the x-axis

2. Translation 6 units to the left and 1 unit up

Step-by-step explanation:

The quadrilateral ABCD has its vertices at points A(3,5), B(6,5), C(4,1) and D(1,1).

1. Reflect quadrilateral ABCD across the x-axis. This reflection has the rule:

$(x,y)\rightarrow (x,-y),$

then

$A(3,5)\rightarrow A'(3,-5)\\ \\B(6,5)\rightarrow B'(63,-5)\\ \\C(4,1)\rightarrow C'(4,-1)\\ \\D(1,1)\rightarrow D'(1,-1)$

2. Translate quadrilateral ABCD 6 units to the left and 1 unit up. This translation has the rule:

$(x,y)\rightarrow (x-6,y+1),$

then

$A'(3,-5)\rightarrow A''(-3,-4)\\ \\B'(6,-5)\rightarrow B''(0,-4)\\ \\C'(4,-1)\rightarrow C''(-2,0)\\ \\D'(1,-1)\rightarrow D''(-5,0)$

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4 years ago

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