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3 years ago

Use the substitution method to solve the following system of equations:

Mathematics

1 answer:

horsena [70]3 years ago

5 0

Answer:

(6, - 3 )

Step-by-step explanation:

Given the 2 equations

3x + 5y = 3 → (1)

x + 2y = 0 → (2)

Rearrange (2) expressing x in terms of y by subtracting 2y from both sides

x = - 2y → (3)

Substitute x = - 2y into (1)

3(- 2y) + 5y = 3

- 6y + 5y = 3

- y = 3 ( multiply both sides by - 1 )

y = - 3

Substitute y = - 3 into (3) for corresponding value of x

x = - 2(- 3) = 6

Solution is (6, - 3 )

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The vertices of a square are its endpoints

The coordinates of the other pairs are: (-1, 3), (4, 3) and (-1, -7), (4, -7)

The given parameters are:

$\mathbf{E = (-1,-2)}$

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Calculate the distance EF

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So, we have:

$\mathbf{EF = \sqrt{(-1 - 4)^2 + (-2 - -2)^2}}$

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Add 5 to the y-coordinates of E and F

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$\mathbf{D = (4,-2+5)}$

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Subtract 5 to the y-coordinates of E and F

$\mathbf{C = (-1,-2-5)}$

$\mathbf{C = (-1,-7)}$

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$\mathbf{D = (4,-7)}$

Hence, the coordinates of the other pairs are: (-1, 3), (4, 3) and (-1, -7), (4, -7)

There is no third pair

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nexus9112 [7]

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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