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3 years ago

Worlds easiest question

Mathematics

2 answers:

Leona [35]3 years ago

5 0

Answer:

Step-by-step explanation:

THERE R 3 LEFT OVER

kobusy [5.1K]3 years ago

4 0

Answer:

B.3 cookies

Step-by-step explanation:

Hope it helps you

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borishaifa [10]

You must first attach the problems with your question.

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3 years ago

Sara had a balance of $350 in her bank account. Her electric bill was $375. After she pays the electric bill, what amount of mon

Alex_Xolod [135]

She should deposit $25.
$375 - $350 = $25

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3 years ago

Which is true about the solution to the system of inequalities shown?

vlabodo [156]

Answer:

Step-by-step explanation:

Which is true about the solution to the system of inequalities shown?

y 3x + 1

y 3x - 3

Only values that satisfy y 3x + 1 are solutions

Only values that satisfy y 3x3 are solutions

Values that satisfy either y a 3x + 1 orys 3x - 3 are solutions

7 0

3 years ago

A division number story with an answer of 12/8?

Natalka [10]

There were 12 cookies and eight cows. Each cow wanted an equal share

of the cookies. How many cookies did each cow get?

Each cow got 1.5 of the cookies, because 12 divided by 8 is 1.5

7 0

3 years ago

Read 2 more answers

Use the substitution x = et to transform the given Cauchy-Euler equation to a differential equation with constant coefficients.

Anika [276]

Answer:

$\boxed{\sf \ \ \ ax^2+bx^{-10} \ \ \ }$

Step-by-step explanation:

Hello,

let's follow the advise and proceed with the substitution

first estimate y'(x) and y''(x) in function of y'(t), y''(t) and t

$x(t)=e^t\\\dfrac{dx}{dt}=e^t\\y'(t)=\dfrac{dy}{dt}=\dfrac{dy}{dx}\dfrac{dx}{dt}=e^ty'(x)y'(x)=e^{-t}y'(t)\\y''(x)=\dfrac{d^2y}{dx^2}=\dfrac{d}{dx}(e^{-t}\dfrac{dy}{dt})=-e^{-t}\dfrac{dt}{dx}\dfrac{dy}{dt}+e^{-t}\dfrac{d}{dx}(\dfrac{dy}{dt})\\=-e^{-t}e^{-t}\dfrac{dy}{dt}+e^{-t}\dfrac{d^2y}{dt^2}\dfrac{dt}{dx}=-e^{-2t}\dfrac{dy}{dt}+e^{-t}\dfrac{d^2y}{dt^2}e^{-t}\\=e^{-2t}(\dfrac{d^2y}{dt^2}-\dfrac{dy}{dt})$

Now we can substitute in the equation

$x^2y''(x)+9xy'(x)-20y(x)=0\\ e^{2t}[ \ e^{-2t}(\dfrac{d^2y}{dt^2}-\dfrac{dy}{dt}) \ ] + 9e^t [ \ e^{-t}\dfrac{dy}{dt} \ ] -20y=0\\ \dfrac{d^2y}{dt^2}-\dfrac{dy}{dt}+ 9\dfrac{dy}{dt}-20y=0\\ \dfrac{d^2y}{dt^2}+ 8\dfrac{dy}{dt}-20y=0\\$