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ioda
2 years ago
10

Un profesor realiza una prueba con 70 preguntas, cada una con igual valor. Un

Mathematics
1 answer:
Valentin [98]2 years ago
3 0

Tenemos un problema sobre porcentajes. Veremos que la calificación del alumno es un 80%.

En este caso sabemos que la prueba tiene 70 preguntas, por lo que la cantidad de referencia (el 100%) será 70.

Y sabemos que el estudiante responde correctamente 56 preguntas.

Lo que queremos hacer es ver que porcentaje representa este segundo número.

Para ver esto planteamos dos ecuaciones:

56 = x

70 = 100%

Para resolver esto, debemos ver el cociente entre esas ecuaciones:

56/70 = x/100%

Ahora resolvemos para x:

(56/70)*100% = x = 80%

Es decir, el alumno obtiene una clasificación del 80%.

Si quieres aprender más puedes leer:

brainly.com/question/18546712

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If 14 out of 20people like chocolate milk, what percent of people don't like chocolate milk?
allsm [11]
The answer should be D. 70%.
Hopefully that helps! :) 
4 0
3 years ago
Read 2 more answers
30 points
igomit [66]
Since the rate of descent is a constant this is a linear equation and can be expressed as:

h=vt+b, where h=feet, v=slope or rate, b=y-intercept (y value when x=0 which is the initial height)

h=-2t+b, using the point (3,67) we can solve for b, or the initial height

67=-2(3)+b

67=-6+b

73=b  so the initial height was 73 ft and the height equation is then:

h(t)=67-2t so when t=8 you have:

h(8)=67-2(8)

h(8)=67-16

h(8)=51 ft
8 0
3 years ago
Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2

<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

3 0
3 years ago
(PLS HELP AND FAST )The edges of three squares are joined together to form a right triangle with legs of lengths /
Elena-2011 [213]

Answer:

R^{2} + S^{2}  = T^{2}

Step-by-step explanation:

the pythagorean theorem

4 0
2 years ago
..........................
AleksandrR [38]

Answer:

Give me a question to answer

3 0
3 years ago
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