C) 22
86/4 = 21.5
*5 Or more, raise the score*
(rounds to 22)
you should have 2 lightbulbs left over but you would be 2 lightbulbs short if you were to get 21 packages as opposed to 22
Answer:
K'= (-1,-1)
J'= (-1,-5)
L'= (0,-3)
Step-by-step explanation:
What you do here is, input the (x,y) coordinates into the translation.
For example, the original point K is (-3,5). Insert this into the translation.
(-3,5) → (-3+2, 5-8) = (-1,-3)
Repeat this for the next coordinates of L and J.
J= (-3,3)
(-3,3) → (-3+2, 3-8) = (-1,-5)
L= (-2, 5)
(-2, 5) → (-2+2, 5-8) = (0,-3)
Answer:
![\sqrt[3]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D)
Step-by-step explanation:
We are required to simplify the quotient: ![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D)
Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:
![\dfrac{\sqrt[3]{60} }{\sqrt[3]{20}} =\sqrt[3]{\dfrac{60} {20}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B60%7D%20%7D%7B%5Csqrt%5B3%5D%7B20%7D%7D%20%3D%5Csqrt%5B3%5D%7B%5Cdfrac%7B60%7D%20%7B20%7D%7D)
![=\sqrt[3]{3}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B3%7D)
The simplified form of the given quotient is .
It depends if you mean like a prism with say 15w 10l and 9h in a horizontal and a prism with a same volume but in a different position. and have a nice day
