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3 years ago

What is 7 over 3 (7/3) times 13 over 8 (13/8)

Mathematics

1 answer:

satela [25.4K]3 years ago

3 0

Answer: It is (91/24) If you want it simplified, then it's (3 19/24)

~hope this helps, have a great day/night my friend!~

Step-by-step explanation:

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Pls answer 9-12 will give brainliest

Elanso [62]

9. $112.50 / 9 lawns = $12.50 per lawn
10. $122.50 / 7 lawns = $17.50 per lawn
11. $112.50 / 7.5 hours = $15.00 per hour
$122.50 / 5 hours = $24.50 per hour
Alastair earns more per hour
12. Taryn: 49 more hours ($735 / $15.00)
Alastaie: 30 more hours ($735 / $24.50)
You found how much money they charge per hour in 11 so use that to find how many hours it takes to earn $735.

6 0

3 years ago

Write the point-slope form of an equation of the line through the points (-7, 7) and (4, 1).

defon

Answer:

y − 7 = − 6 /11 ⋅ ( x + 7 )

Step-by-step explanation:

Find the point-slope form.

Point-slope formula: y-y₁=m(x-x₁)

3 0

3 years ago

(t-2)(t+1)(t+1) what is this when foiled out

mario62 [17]

(t-2)(t+1)(t+1)
t^2+t-2t-2(t+1)
t^2-t-2(t+1)
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3 0

3 years ago

Read 2 more answers

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = 1586 m

Fencing required = 1586 m

4 0

3 years ago

Evaluate 3^3+4*6 pls i need it for sumthing really quick

Masja [62]

Answer : 4123

Explanation:

8 0

3 years ago