The equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3
The line is passing through the point = (-6,-3)
The slope of the line = 0
The point slope form is

Substitute the values in the equation
(y-(-3)) = 0×(x-(-6))
We have to convert this equation the slope intercept form
Slope intercept form is
y = mx + b
Where m is the slope of the line
b is the y intercept
(y-(-3)) = 0×(x-(-6))
y+3 = 0×(x+6)
y+3 = 0
y = -3
Hence, the equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3.
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2(5x)2(-7)=2x+10
2(5x)= 10x
2(-7)=-14
10x-14=2x+10
Solve:
10x-2x=8x
8x-14=10
14+10=24
8x=24
24/8=3
X=3
Answer:
vertex = 
Intercepts for x = 
intercepts for y = (0,-6)