You can write this two ways - as a list of prime factors, or combine like factors and represent their quantity with an exponent.
If you begin by dividing by two, you can do that six times, with a three as the remaining prime factor.
2·2·2·2·2·2·3
OR
2∧6 · 3
Answer:
61 , 63 , 65 , 67
Step-by-step explanation:
Let the least even number be denoted by x. The sum of the four consecutive even numbers would be:
(x) + (x + 2) + (x + 4) (x + 6) = 256
First, simplify. Combine all like terms:
x + x + x + x + 2 + 4 + 6 = 256
4x + 12 = 256
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 12 from both sides of the equation:
4x + 12 (-12) = 256 (-12)
4x = 256 - 12
4x = 144
Next, divide 4 from both sides of the equation:
(4x)/4 = (144)/4
x = 144/4
x = 61
61 is your first number. Find the next 3 consecutive numbers:
x = 61
x + 2 = 63
x + 4 = 65
x + 6 = 67
Check:
61 + 63 + 65 + 67 = 256
256 = 256
~
Answer:
Step-by-step explanation:
Isolate the term of n from one side of the equation.
<h3>n-1/8=3/8</h3>
<u>First, add by 1/8 from both sides.</u>
n-1/8+1/8=3/8+1/8
<u>Solve.</u>
<u>Add the numbers from left to right.</u>
3/8+1/8=4/8
<u>Common factor of 4.</u>
4/4=1
8/4=2
<u>Rewrite as a fraction.</u>
=1/2
n=1/2
<u>Divide is another option.</u>
1/2=0.5
n=1/2=0.5
- <u>Therefore, the final answer is n=1/2=0.5.</u>
I hope this helps you! Let me know if my answer is wrong or not.
