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ohaa [14]
3 years ago
13

the endpoints of segment LE are L(-2,2) and F(3,1). the endpoints of segment JR are J(1,-1) and R(2,-3). what is the approximate

difference in the lengths of the two segments?
Mathematics
2 answers:
Alenkinab [10]3 years ago
7 0
Just think a bit don’t procrastinate! You got this
Snezhnost [94]3 years ago
7 0
S=~ 5.099 is the awnser
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Solve The Equation, Check Your Answer 15=7x+1-5x
Morgarella [4.7K]
15=7x+1-5x


Put like terms together. ( group anything alike)

15+1=16

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—- ——-
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5 0
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7.<br>(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)​
serg [7]

Answer:

-\frac{x^2y^2}{2}

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}

Multiply the numerators :

\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}

Multiply the denominators :

\frac{-18x^6y^4z^3}{36x^4y^2z^3}

Apply the negative rule :

-\frac{18x^6y^4z^3}{36x^4y^2z^3}

Cancel the common factor which is 18 :

-\frac{x^6y^4z^3}{2x^4y^2z^3}

Apply the addition exponent rule :

\frac{y^4z^3x^{6-4} }{2y^2z^3}

Subtract :

\frac{x^2y^4z^3 }{2y^2z^3}

Apply the rule for y :

\frac{x^2y^{4-2} z^3 }{2z^3}

Subtract :

\frac{x^2y^2z^3 }{2z^3}

Cancel the common factor of z^3 :

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5 0
3 years ago
Can someone help me with this 2 step eqaution
Snowcat [4.5K]
The answer is:  " 40 books " .
____________________________________________
Explanation:
____________________________________________
Let "x" equal the number of books that Jill started with.  Solve for "x" :
____________________________________________
         x – (1/2)x  + 16 = 36 ;

1x – (1/2)) = (1/2)x ; 

(1/2)x + 16 = 36 ; 

Subtract "16" from EACH SIDE of the equation:

(1/2)x + 16 – 16 = 36 – 16  ; 

(1/2)x = 20 ; 

Multiply each side of the equation by "2" ; 

2*(1/2)x = 20 * 2 ; 

to get:  x = 40 . 
____________________________________________
The answer is:  " 40 books " .
____________________________________________
5 0
3 years ago
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