The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(
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Answer:
A).3222
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they are from Latvia, or they are not. We are choosing students without replacement. However, since the sample size is large, we can use the binomial distribution to approximate the hypergeometric distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
480 students, of which 96 are from Latvia:
This means that
Sample of 10 students:
This means that
Probability that the sample contains at least three Latvian students.
Either there are less than three students from Latvia, or there are at least three. The sum of the probabilities of these events is 1. So
We want , in which:
So
So
The closest option is A.
Answer:
Surface Area: 310 square inches.
Step-by-step explanation:
There are two ways to do this:
A) Formula for Surface Area of a Rectangular Prism = 2 * ( l*w + w*h + h*l). Where l is length, w is width & h is height. Based on the question:
l = 10 inch
w = 5 inch
h = 7 inch
Surface Area = 2 * ( 10*5 + 5*7 + 7*10) = 310 square inches.
B) Formula for Area of Rectangle = l*w, where l is length & w is width.
Look at the picture, I have marked the corners O,P,Q,R,S,T,U,V,W,X,Y,Z
If we calculate the Area of each rectangle and add them all we will get the surface area automatically.
- Area of PQRS = 10*7 = 70 square inches
- Area of STUV = 7*5 = 35 square inches
- Area of VWXY = (7+5)*10 = 120 square inches
- Area of ORYZ = 7*5 = 35 square inches
- Area of RSVY = 10*5 = 50 square inches
Now add them all = 70+35+120+35+50 = 310 square inches.
