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7nadin3 [17]
2 years ago
8

What equals (−1)+(−2) using the number line.

Mathematics
2 answers:
hodyreva [135]2 years ago
6 0

Answer: -3

Step-by-step explanation:

(-1)+(-2)=-3

Goryan [66]2 years ago
3 0

Answer:

-3

Step-by-step explanation:

2+1=3 and just add the negative sign in front of it.

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Help me solve this? ​
LiRa [457]

Answer:

Step-by-step explanation:

5(-5)-2=-27

5(-2)-2= -12

5(1)-2=3

5(2)-2=8

5(3)-2=13

x     g(x)

-5   -27

-2    -12

1        3

2      8

3      13

5 0
3 years ago
Read 2 more answers
How do you solve 9| x+8 | + 10 < 55 & how is it graphed
mafiozo [28]
Hello!

First, let's write the problem.
9\left|x+8\right|+10\ \textless \ 55|x+8|+10\ \textless \ 55
Subtract 10 from both sides.
9\left|x+8\right|+10-10\ \textless \ 55-10
9\left|x+8\right|\ \textless \ 45
Divide both sides by 9.
\frac{9\left|x+8\right|}{9}\ \textless \ \frac{45}{9}
\left|x+8\right|\ \textless \ 5
When we got absolute value, we are going to get two results.
x+8\ \textless \ 5
and
x+8\ \textgreater \ -5

Let's solve the first one,
x+8\ \textless \ 5x+8\ \textless \ 5
Subtract 8 from both sides.
x+8-8\ \textless \ 5-8
x\ \textless \ -3x\ \textless \ -3

Let's solve the second one.
x+8\ \textgreater \ -5
Subtract 8 from both sides.
x+8-8\ \textgreater \ -5-8
x\ \textgreater \ -13x\ \textgreater \ -13

Let's combine the ranges.
-13\ \textless \ x\ \textless \ -3

The attachment shows how would you graph it.
You can feel free to let me know if you have any questions regarding this.
Thanks!

- TetraFish

3 0
3 years ago
What value of x makes the proportions true?
Marianna [84]
The answer is 9.
6x4=24
?x4=36
3 0
3 years ago
Read 2 more answers
Sarah has tickets numbered 12 – 24 in a bag. She pulls one ticket without looking and replaces it after each pull. What is the t
natima [27]
12-24=12 and so you multiply 5x12 and you get 60
3 0
2 years ago
(ab+3)^2 find the product
Alenkasestr [34]

Answer :

(ab+3)2

Steps :

Final result :

(ab + 3)2

Step by step solution :

Step 1 :

Final result :

(ab + 3)2

8 0
3 years ago
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