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lbvjy [14]
3 years ago
10

Two linear equations are represented by using the tables below. A 2-column table with 4 rows is titled Equation A. Column 1 is l

abeled x with entries negative 5, negative 2, 0, 1. Column 2 is labeled y with entries negative 4, negative 1, 1, 2. A 2-column table with 4 rows is titled Equation B. Column 1 is labeled x with entries negative 6, negative 3, 3, 6. Column 2 is labeled y with entries negative 4, negative 2, 2, 4. The data points for equation A are plotted on the coordinate plane below and are connected by using a straight line.
Mathematics
2 answers:
Anit [1.1K]3 years ago
6 0

Answer:

Mr. John is a small business man that run a Hardware, he have been experiences problem with his small accounting department which he depends on to provide him with the sales reports. Mr. John want to be able to shared information between his 7 computer station and have on central printing area, what type of network would you recommend to Mr. John? *

1 point

A. MAN

B. LAN

C. WAN

D. SAN

leonid [27]3 years ago
4 0

Answer:

C. (–3, –2)

Step-by-step explanation:

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Xy′ = √(1 − y2 ), y(1) = 0
tigry1 [53]

Answer:

y=sin(ln(x))

Step-by-step explanation:

First, we have to order the terms as follows and express y' as dy / dx:

x*\frac{dy}{dx} =\sqrt{(1-y^{2} )} \\\frac{x}{dx}=\frac{dy}\sqrt{(1-y^{2} )}}\\\frac{dx}{x}=\frac{dy}{\sqrt{(1-y^{2} )} }

Then, we have to integrate

\int{\frac{dx}{x}=\int{\frac{dy}{\sqrt{(1-y^{2} )} }

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Then, we have to reorder

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and applied Sin function on both sides

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To define the value of C, we use the known point y(1)=0 and replace in the equation

y=sin(ln(x)+C)\\0=sin(ln(1)+C)\\0=sin(0+C)\\0=sin(C)\\C=arcsin(0)\\C=0

The function that proves that differential equation is

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