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sergey [27]
3 years ago
11

What is the surface area of the square pyramid?

Mathematics
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

Right square pyramid

Solve for surface area

A=a2+2aa2

4+h2

a Base edge

Enter value

h Height

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Points A and Blie in plane R. Line AB does not lie in plane R.<br> always<br> sometimes<br> never
FinnZ [79.3K]

Answer:

Never

Step-by-step explanation: If two points are on the same plane but a line containing those two points is not on the same plane, the statement will never be true. Picture a cube and on one face of the cube lies two points, if there is a line containing those points, the line also has to be on the same side or face. It will always run parallel to the same side but will also always be touching that side.

4 0
3 years ago
the ratio of pink marbles to white marbles in Samaras bag is equal to 1:5. what percent of the bag contains pink marble
kenny6666 [7]
1:5= 1/5 x 20/20= 20/100

20/100= 0.20

The bag contains 20% of pink marbles.
3 0
4 years ago
The following numerically ordered sequence of numbers has a mean
Vladimir79 [104]
Median =  middle number

Total ten numbers so 
median =   (17 + b)/2
given median = 18
so
(17 + b)/  2 = 18
17+b = 36
b = 36 - 17
b = 19

Now you have the data set
7, a , 12, 15 , 17, 19, 20, 22, 24 , 25

Mean =  (7 + a + 12+ 15 +17 + 19 + 20 + 22 +24  +25)/ 10
Given mean = 17

so
17 = (7 + a + 12+ 15 +17 + 19 + 20 + 22 +24  +25)/ 10
17 = (a + 161) / 10
a + 161 = 170
a = 170 - 161
a = 9

answer
a = 9
b = 19
7 0
3 years ago
Read 2 more answers
The equation y-3=-2(x+5) is written in point-slope form. What is the y-intercept of the line? *
yawa3891 [41]

Answer:

-7

Step-by-step explanation:

y-intercept

x=0

y-3= -2x-10

y=2(0)-10+3

y=0-7

y= -7

(0;-7)

6 0
3 years ago
Read 2 more answers
What is the surface area of this design? 5 in 5 in 6.4 in 5 in 9 in
xeze [42]

ANSWER

197 {in}^{2}

EXPLANATION

The area of the two tra-pezoidal faces

= 2 \times  \frac{1}{2}  \times (9 + 5) \times 5 = 70 {in}^{2}

The area of the 5 by 6.4 rectangular face

= 6.4 \times 5 = 32  {in}^{2}

The area of the two square faces

= 2(5 \times 5) = 50 {in}^{2}

The area of the 9 by 5 rectangular face is

= 9 \times 5 = 45 {in}^{2}

The surface area of the design is:

70 + 32 + 50  + 45=197 {in}^{2}

6 0
3 years ago
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