Well if its between 10 & 20 take the median which is 15 and multiple it by the about of days which is 56 and you get 840 dollars <span />
So, he had 2 thirds then removed 2 sixths. You have to subtract the fractions.
2 sixths is equal to 1 third.
2 thirds-1 third= 1 third.
Grant has 1/3 of a cup of ice cream left in his bowl.
I hope this helped!
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The relative frequency of students who are not seniors at this high school will be 82.96%.
<h3>How to find how much percent 'a' is of 'b'?</h3>
Suppose a number is 'a'
Suppose another number is 'b'
We want to know how much percent of 'b' is 'a'.
Then, it is calculated as:
P = a/b × 100
A local high school has 1,203 students with 367 freshmen, 382 sophomores, 249 juniors, and 205 seniors.
Then the relative frequency of students who are not seniors at this high school will be
P = 998/1203 × 100
P = 0.82959 × 100
P = 82.959%
P ≈ 82.96%
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Answer:
14 minutes
Step-by-step explanation:
4 x every 100 bottles
100, 200, 300 = 3
4 x 3 = 12
if 4 minutes is for every 100 bottles, then 50 is half of 100. so 4 divided by 2 is 2
12 + 2 = 14
Answer:
The answer to the given problem is provided below.
Step-by-step explanation:
She can make the conclusion at 95% confidence level that average sales have increased:
Since the sample mean, $2,984, falls outside the range of likely sample means (which has an upper bound=$2,843.44), the store owner can reject the null hypothesis that μ≤ $2,700 μ≤ $2,700 at a 95% confidence level.
Since she can reject the null hypothesis, she can essentially accept the alternative hypothesis and conclude the average daily sales have increased.
