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2 years ago

7

State the horizontal asymptote of the rational function. f(x) = 3x^2 -4x -3/ 2x^2 - 3x+2

1 answer:

irina1246 [14]2 years ago

3 0

Answer:

Step-by-step explanation:

$\displaystyle \lim_{x \to \infty} \dfrac{3x^2-4x-3}{2x^2-3x+2} =\dfrac{3}{2} \\$

Horizontal asymptote has for equation y=3/2

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the answer to your question is -8

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3 years ago

Solve x^2 – 8x + 41 = 0 for x.

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Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel

GarryVolchara [31]

Answer:

The unusual $X$ values for this model are: $X = 0, 1, 2, 7, 8$

Step-by-step explanation:

A binomial random variable $X$ represents the number of successes obtained in a repetition of $n$ Bernoulli-type trials with probability of success $p$ . In this particular case, $n = 8$ , and $p = 0.53$ , therefore, the model is ${8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}$ . So, you have:

$P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024$

$P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215$

$P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848$

$P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912$

$P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695$

$P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431$

$P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371$

$P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442$

$P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062$

The unusual $X$ values for this model are: $X = 0, 1, 7, 8$

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3 years ago

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The average time between infection with the AIDS virus and developing AIDS has been estimated to be 8 years with a standard devi

Dahasolnce [82]

Answer:

1/40

Step-by-step explanation:

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2 years ago

Gavin and his three friends want to share 1/3of cake equally. Gavin says that each friend will get 1/9 of the cake. Use the drop

Alexxandr [17]

Answer: Incorrect

Step-by-step explanation:

Given

Gavin and his three friends wants to share $\frac{1}{3}$ of cake equally.

So, there are 4 members to distribute the cake

Each member will get

$\Rightarrow \dfrac{\dfrac{1}{3}}{4}\\\\\Rightarrow \dfrac{1}{3\times 4}=\dfrac{1}{12}$

So, each member get one-twelvefth of the given cake.

Hence, Gavin is incorrect.

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3 years ago

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