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Ludmilka [50]
3 years ago
5

Find the LCM and HCF of 15, 42 and 123

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:

LCM - 1

HCF - 3

Step-by-step explanation:

LCM - Lowest Common Factors

HCF - Highest Common Factors

____________________________________________________________

Factors of 15 - 1, 3, 5, 15

Factors of 42 - 1, 2, 3, 6, 7, 14, 21, 42

Factors of 123 - 1, 3, 41, 123

So now we know the factors of 15, 42, 123 what is lowest and highest factor we can find in every number

____________________________________________________________

I have bolded the lowest and highest common factor.

Factors of 15 - 1, 3, 5, 15

Factors of 42 - 1, 2, 3, 6, 7, 14, 21, 42

Factors of 123 - 1, 3, 41, 123

_______________________________________________

LCM - 1

HCF - 3

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If the average yield of cucumber acre is 800 kg, with a variance 1600 kg, and that the amount of the cucumber follows the normal
lorasvet [3.4K]

Answer:

a

   The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

b

   The probability is  P(Z >  2.5 ) =  0.0062097

Step-by-step explanation:

From the question we are told that

        The  population mean is  \mu =  800

        The  variance is  var(x) =  1600 \ kg

        The  range consider is  x_1 =  778 \ kg  \  x_2 =  834 \ kg

         The  value consider in second question is  x =  900 \ kg

Generally the standard deviation is mathematically represented as

        \sigma =  \sqrt{var (x)}

substituting value

        \sigma =  \sqrt{1600}

       \sigma = 40

The percentage of a cucumber give the crop amount between 778 and 834 kg  is mathematically represented as

       P(x_1 <  X <  x_2 ) =  P( \frac{x_1 -  \mu }{\sigma} <  \frac{X - \mu }{ \sigma } < \frac{x_2 - \mu }{\sigma }   )

    Generally  \frac{X - \mu }{ \sigma } = Z (standardized \  value  \  of  \  X)

So

      P(x_1 <  X <  x_2 ) =  P( \frac{778 -  800 }{40} < Z< \frac{834 - 800 }{40 }   )

      P(x_1 <  X <  x_2 ) =  P(z_2 < 0.85) -  P(z_1 <  -0.55)

From the z-table  the value for  P(z_1 <  0.85) =  0.80234

                                            and P(z_1 <  -0.55) =   0.29116  

So

             P(x_1 <  X <  x_2 ) =   0.80234 - 0.29116

             P(x_1 <  X <  x_2 ) =   0.51118

The  percentage is

            P(x_1 <  X <  x_2 ) =   51.1 \%

The probability of cucumber give the crop exceed 900 kg is mathematically represented as

             P(X > x ) =  P(\frac{X - \mu }{\sigma }  > \frac{x - \mu }{\sigma } )

substituting values

             P(X > x ) =  P( \frac{X - \mu }{\sigma }  >\frac{900 - 800 }{40 }   )

             P(X > x ) =  P(Z >2.5   )

From the z-table  the value for  P(Z >  2.5 ) =  0.0062097

 

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4 years ago
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puteri [66]

Answer: x=6 and the angle is 50

Step-by-step explanation:

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3. subtract 2 from 50 and get 48

4. divide 48 by 8 and you get 6.

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2/5 more i believe!
basically just subtract 4/5 and 2/5 and you get 2/5
feel free to mark brainliest, hope this helps!
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Read 2 more answers
Alan is comparing the cost of a fresh lobster dinner at two different restaurants. The first
Pepsi [2]

Good evening ,

Answer:

The weight : 29 pound

Alan would pay for his dinner : $130

Step-by-step explanation:

Let x represent the weight of the lobster

the cost of the dinner at restaurant 1 is 4x + 14  

the cost of the dinner at restaurant 2 is 3x + 43

Now ,we have to solve the equation :  4x + 14 = 3x + 43

4x + 14 = 3x + 43

⇔ x = 43 - 14

⇔ x = 29

In this case Alan would pay the same amount for his dinner at any restaurant:

the price = 4×(29)+14 = 130

               = 3×(29)+43 = 130.

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Answer:

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Step-by-step explanation:

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20500/16=1281.25

1281.25/100= 12.8125

rounded 12.81%

7 0
3 years ago
Read 2 more answers
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