Speed=distance/time
suppose the distance of the first day is d, and the time is t
distance of the second day: d+0.17d=1.17d
time of the second day: t+0.2t=1.2t
speed of the second day: 1.17d/1.2t=0.975(d/t)=(1-0.025)(d/t)
so the speed of the second day is 2.5% slower than the first day.
Answer:
a. $45 an hour
b. 5.25 hours
Step-by-step explanation:
a. The plumber charges $75 per job, so it is irrelevant to the number of hours they work. 45(h) is $45 multiplied by the number of hours they work.
b.
First, plug the numbers into the equation, the cost being C(h):
311.25 = 45(h) + 75
Next, subtract $75 as it is a set price that is always payed:
236.25 = 45(h)
Then, divide both sides by 45 to find how many hours were worked:
h = 5.25
Hours = $5.25
Answer:4
Step-by-step explanation:
Given f(x)=2x, if (x)=14, find x
x=3
