Answer:
Area = 160 cm²
Perimeter = 55.31 cm
Step-by-step explanation:
Applying,
Area of the figure = area of the rectangle- area of the triangle
A = lw+bh/2............... Equation 1
From the question,
Given: l = 16 cm, w = 12 cm, h = 8cm, b = 8 cm
Substitute these values into equation 1
A = (16×12)-(8×8/2)
A = 192-32
A = 160 cm²
Perimeter P = /BC/+/CD/+/DE/+/EF/+/FG/+/GA/
Applying pythagoras theorem to get /FG/
FG² = GE²+EF²
FG² = 8²+8²
FG² = 64+64
FG² = 128
FG = √128
FG = 11.31 cm
Therefore,
P = 16+12+4+8+11.31+4
P = 55.31 cm
I’m pretty sure it is 57?
Answer:
the number that occures the most is the answer
Step-by-step explanation:
No. Not all radical equations have an extraneous solution. <span>However, squaring both sides of an </span>equation<span> can create </span>extraneous solutions.<span>
hope this helps :)</span>
