Sin angle that equals the 1/2 value is the 30 degree on the 1st Quadrant.
The angle of 30 degree on the 3rd Quadrant is equivalent to (formula and circle in the 1st photo) 180 + 30 = 210°.
So theta = 210° (3rd Quadrant) = 30° (1st Quadrant).

Now just transfer the cos 30° to the 3rd Quadrant and the signal will be negative (as shown in the 2nd photo attached).
Can someone please go over to my page and help me with this problem, its worth 99 points,no joke
Step-by-step explanation:
dy/dx
= d/dx [x / (1 - x²)]
= [(1 - x²)(1) - (x)(-2x)] / (1 - x²)²
= (1 + x²) / (1 - x²)².
When dy/dx = 1, (1 + x²) / (1 - x²)² = 1.
=> 1 + x² = 1 - x²
=> 2x² = 0, x = 0.
Also when x = 0, y = (0) / [1 - (0)²] = 0.
Hence the coodinates is (0, 0).