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2 years ago

Someone help me with 12 I don’t understand stand this question someone please help me with work shown

Mathematics

1 answer:

allochka39001 [22]2 years ago

5 0

2x+8+ 120= 180
Combine like terms so 8+120=128

2x+8+ 120= 180
2x+128=180
-128=-128 ( to both side)
2x= 52 You divide now
2x/2= 52/2
x= 26
There is your answer :)

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. The total area of a rectangular mural has been extended by x feet. The expression to represent the area is 5.5(7.5 + x). Rewri

alexandr1967 [171]

Answer and Step-by-step explanation: <u>Distributive</u> <u>Property</u> describes how to solve expressions like a(b +c). According to the property, multiplying the sum of two or more numbers by a number will result in the same as multiplying each number and then add the products. For example:

11(2 + 4)

11(6) = 66 22 + 44 = 66

So, for the expression that represents the area:

5.5(7.5 + x) = 41.25 + 5.5x

As the expression has non-numerical terms, the distributive property will be multiply each term and then add the products.

The expressio for area of a rectangular mural is 41.25 + 5.5x.

7 0

3 years ago

0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?

MakcuM [25]

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

We now find 2#

2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

We now find 1#

1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So, 4# · 3# · 2# · 1#? = 6912 · 24 · 2 · 1? = 331776

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2 years ago

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dezoksy [38]

The question is unclear.

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2 years ago

If f(x)= 3 over x+2- square root x-3 f(19)=

PSYCHO15rus [73]

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= (3/21) - sqrt(16)
= (1/7) - 4
= (1/7) - (28/7)
= -27/7
= - 3 6/7

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3 years ago

5. what is the theoretical probability that a coin toss results in one head and one tail showing?

Alenkasestr [34]

There are two sides (heads and tails). So one head would be 1/2, and one tail would also be 1/2.

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2 years ago