Answer:
if it is put into a equation this would be it
2(x^2+6x+9) - (1.57)(x^2+6x+9)
Step-by-step explanation:
(x+3)(2x+6) - 1/2(3.14)(x+3)(x+3)
(2x^2+6x+6x+18) - 1/2(3.14)(x^2+3x+3x+9)
(2x^2+12x+18) - 1/2(3.14)(x^2+6x+9)
2(x^2+6x+9) - (1.57)(x^2+6x+9)
2(x^2+6x+9) is the rectangle at the bottom
(1.57)(x^2+6x+9) is the semicircle that is taking out of the shaded area
Answer:

Step-by-step explanation:
we are given

we can simplify left side and make it equal to right side
we can use trig identity


now, we can plug values

now, we can simplify



now, we can factor it

![\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28sin%28a%29%2Bcos%28a%29%29%5B3-4%28sin%5E2%28a%29%2Bcos%5E2%28a%29-sin%28a%29cos%28a%29%5D%7D%7Bsin%28a%29%2Bcos%28a%29%7D%20)
we can use trig identity

![\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28sin%28a%29%2Bcos%28a%29%29%5B3-4%281-sin%28a%29cos%28a%29%5D%7D%7Bsin%28a%29%2Bcos%28a%29%7D%20)
we can cancel terms

now, we can simplify it further




now, we can use trig identity

we can replace it

so,

Answer:
,..............,...............?..?.?.?.?.................
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
24*.75=18