20 points Help Of the 30 girls who tried out for the basketball team at SMS, 12 were

Mathematics

1 answer:

Kisachek [45]3 years ago

8 0

Answer:

yes

Step-by-step explanation:

Girls:

12 girls out of 30

12/30

Divide the top and bottom by 6

2/5

Boys

16 out of 40

Divide the top and bottom by 8

2/5

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how much would $150 invested at 8% interest compounded anually be worth after 13 years? A(t)=P(1+r/n)^

PIT_PIT [208]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$150\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &13
\end{cases}
\\\\\\
A=150\left(1+\frac{0.08}{1}\right)^{1\cdot 13}\implies A=150(1.08)^{13}\implies A\approx 407.9435589$

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3 years ago

Subtract and reduce: 2 2/3 - 1 1/2

babunello [35]

Step-by-step explanation:

I used a calculator but the answer is 1 1/6

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If a country's debt-to-GDP ratio is currently 5% and its debt is expected to

Valentin [98]

400 billion dollars

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3 years ago

Read 2 more answers

The distances male long jumpers for State College jump are approximately normal with a mean of 263 inches and a standard deviati

Effectus [21]

Answer:

His jump was of 272.45 inches

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 263, \sigma = 14$