Can someone please help me?!

Mathematics

2 answers:

koban [17]3 years ago

7 0

Answer:

The answer would be B. X . 3/2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Hope this helps good luck! :)

MArishka [77]3 years ago

6 0

Answer:x3

Step-by-step explanation:

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How do I solve this problem?

erica [24]

I forgot which theorem it is but it basically says that the side across from the smallest angle in the triangle is the smallest side and the side across the largest angle is the largest side. This means that HK and JK are equal and HJ is the largest side. (So ig HK < JK < HJ)

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3 years ago

Is 5/16 equal or bigger than 1/2

taurus [48]

To be able to compare two fraction we have to make common denominator. Then we can compare fractions.
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3 years ago

Read 2 more answers

A=(2 3)<br> (-1 4)<br><br> Calculate A^2-6A+11I

disa [49]

Answer:

A² - 6A + 11 I = $\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]$

Step-by-step explanation:

Given the matrix

$A=\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right]$

Calculate A² - 6A + 11 I

$A^2 = A*A= \left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] *\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] = \left[\begin{array}{ccc}2*2-3*1&2*3+3*4\\-1*2-4*1&-1*3+4*4\end{array}\right] =\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right]$

$6A=6*\left[\begin{array}{ccc}2&3\\-1&4\end{array}\right] =\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right]$

$11 I = 11 * \left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =\left[\begin{array}{ccc}11&0\\0&11\end{array}\right]$

∴ A² - 6A + 11 I = $\left[\begin{array}{ccc}1&18\\-6&13\end{array}\right] -\left[\begin{array}{ccc}12&18\\-6&24\end{array}\right] +\left[\begin{array}{ccc}11&0\\0&11\end{array}\right] =\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]$