Hypertonic solution: higher concentration outside of cell = lower water potential = water exits cell, cell shrink (crenated-animal cell, flaccid/plasmolysed-plant cell)
Hypotonic solution: lower concentration outside cell =higher water potential = water enters cell, cell swell (animal cell - burst,plant cell - turgid)
Let us solve first the
phenotype of this problem.
Starchy grain = AA (dominant)
Sugary Corn = aa (recessive)
AA x aa = AaAa ; AaAa
<span> A A</span>
<span>a Aa Aa</span>
<span>a Aa Aa</span>
The result of the cross is
that the progeny will become heterozygous.
<span>If there is 58 progeny
sugary, there will also be 58 starchy. It is 50%.</span>
The Potential Unemployment is one of the negative outcome
The F1 offspring of Mendel's classic pea plant crosses always looked like one of the two parental varieties because he crossed a homozygous dominant plant with a homozygous recessive plant so each plant received one recessive allele and one dominant allele. All of the plants looked like one plant because the dominant allele overshadowed the recessive allele
Answer:
A. ovary
Explanation:
It takes place in a fallopian tube that links an ovary to the uterus.
Hope this Helps!
