Member Price = 30 + 3x
Non-member Price = 6x
x = the tickets they buy.
We want 30 + 3x = 6x
So, first we subtract 3x from each side and are left with:
30 = 3x
Then, divide each side by 3.
10 = x
So, the cost of 10 tickets is the same more non-members and members.
We can also check it:
Member Price: 30 + 3(10)
30 + 30 = 60
Non-member Price: 6(10)
60
Answer:
(a) 120 choices
(b) 110 choices
Step-by-step explanation:
The number of ways in which we can select k element from a group n elements is given by:

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

Then each student have 120 possible choices.
On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:
1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:
50 + 50 + 10 = 110
Answer:
ok can you give the link
Step-by-step explanation:
Answer:
g(t) = 10000(0.938)^t
Step-by-step explanation:
Given data:
car worth is $10,000 in 2012
car worth is $8000 in 2014
let linear function is given as
P(t) = at + b
which denote the value of car in year t
take t =0 for year 2012
at t =0, 10,000 = 0 + b
we get b = 10,000
take t =2 for year 2014
at t =2, P(2) = 2a + b
8800 = 2a + 10,000
a = - 600
Thus the price of car at year t after 2012 is given as p(t) = -600t + 10000
let the exponential function
where t denote t = 0 at 2012
putting t = 0 P(0) = 10,000 we get 10,000 = ab^0
a = 10,000
putting t = 2 p = 8800


b = 0.938
g(t) = 10000(0.938)^t
40960000 is the answer to the equation